The answers 646 :) it’s just subtracting the withdrawals from 1000 then adding the last one
Answer:
Given: Consider a triangle ABC in which AD is median drawn from vertex A.
To prove: AB + AC > AD
Proof: In Δ A B D
AB + B D> AD ⇒[In a triangle sum of lengths of two sides is greater than the third side] .................(1)
In Δ A CD
AC + DC > AD [In a triangle sum of lengths of two sides is greater than the third side] .................(2)
Adding (1) and (2)
AB + AC+ B D + D C > B D + DC
A B+ A C+ B C > 2 B D .................(3)
Also , Considering Δ AB C
AB + B C > B C ⇒[In a triangle sum of lengths of two sides is greater than the third side]
⇒ AB + B C - B C >0 ........................(4)
Adding (3) and (4)
A B+ B C+B C+ AB +A C- B C > 2 A D
⇒2 AB + 2 A C> 2 A D
Dividing both side of inequality by 2, we get
A B+ A C> A D
Hence proved.
Find 4% of 70
4% of 70 means
4/100 times 70 or
280/100 or
2.800
he would earn $2.80 comission
Answer:
17.85 feet.
Step-by-step explanation:
Area = 1/4 * 3.14 * r^2 where r is the radius
So r^2 = 19.625 / (1/4 * 3.14)
r^2 = 25
r = 5 feet.
The perimeter = 2r + 1/4 * 2* 3.14*r
= 2*5 + 7.85
= 17.85 feet.
Formula for point-slope:

Plug in the values (1):

{Choice B}
Plug in the values (2):

{Choice C}
_______________________
[For (3) and (4) we need to solve for slope]
(3)
First, solve for slope.
Formula for slope:

Plug in values:

Slope:

Second, we must plug into point-slope form.
Formula for point-slope:

Plug in the values:

{Choice C}
(4)
First, solve for slope.
Formula for slope:

Plug in values:

Slope:

Second, we must plug into point-slope form.
Formula for point-slope:

Plug in the values:

{Choice D}