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Rainbow [258]
3 years ago
10

Please help me with this math question T-T

Mathematics
1 answer:
Arisa [49]3 years ago
5 0
1400000000000000000000000
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What is the area of the trapezoid shown below?​
Olin [163]

Answer:

78 sqr units

Step-by-step explanation:

Use the Pythagorean Theorem to help find the base opposite the two.

The base of the second parallel line is sqrt(  (15^2) - (12^2)  ) = sqrt(81) = 9

The second base = 9 + 2 = 11

Area = (b1 + b2)*h/2

h = 12

b1 = 2

b2 = 11

h = 12

Area = (11 + 2)*12/2

Area = 13 * 12/2

Area = 78 square units

7 0
3 years ago
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-22 + (-16)<br> Hhhhhhhhhhhhhhhhhhhhhh
Ad libitum [116K]

Answer:

-22 + (-16)= -38

Step-by-step explanation:

6 0
3 years ago
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Find -sqrt(36<br> O t6<br> O -6<br> O 6<br> O 18
gavmur [86]
-sqrt(36) = -6

Hope this helps :)
8 0
3 years ago
Posting a screenshot.
Anna71 [15]
Since 6 is positive, it's (x+blank)^2

6/2=3, and (x+3)^2 = x^2+6x+9. We have x^2+6x-2, so we have to add 9 to both sides to get (x+3)^2-2=9, then subtract 9 from both sides to get
(x+3)^2-11=0, or (x+3)^2=11. Square root both sides to get x+3=sqrt(11), and x=sqrt(11)-3, which is approximately 0.32
8 0
3 years ago
Find the slope of this line.
natulia [17]

Answer:

4/5

Step-by-step explanation:

SImply use slope formula. We see the graph has defined points at (5, 4), and (-5, -4).

m=(Y2-Y1)/(X2-X1)

(4-(-4))/(5-(-5))=8/10

Simplify 8/10

=4/5

4 0
2 years ago
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