Substituting <em>x</em> with <em>π</em>/2 - <em>x</em> gives the equivalent integral,
So if we let <em>J</em> denote the value of the integral, we have
Condensing the logarithms, we have
log(tan(<em>x</em>)) + log(cot(<em>x</em>)) = log(tan(<em>x</em>) cot(<em>x</em>)) = log(1) = 0
since cot(<em>x</em>) = 1/tan(<em>x</em>), which means
and so the original integral has a value of <em>J</em> = 0.
Answer:
x = 4
Step-by-step explanation:
6x - 8 = 16
Add 8 to both sides.
6x = 24
Divide both sides by 6.
x = 4
First, let's find the time where the ship arrives to point C
t=d/V, t= 45/30=1.5h
if the ship's departure time is at 1.5h, on the point C, let 's find its arrival to the point O, V=D/Dt, Dt=tfinal-tinitial
Dt=D/V= 20/30=0.6h=t final -t initial, implies t final=0.6+t initial=0.6+1.5=2.1h
so the ship will be on the radar at 2.1h,
Answer:2 2/15
Step-by-step explanation:
4/5= 12/15
+1 1/3 =5/15
1 and 17/15
17/15= 1 and 2/15 +1= 2 and 2/15
Answer:
X=-3
Step-by-step explanation:
5x - 9
-2x + 12
(+) (-)
7x = -21
X= -3
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