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Mila [183]
3 years ago
12

PLS HELP. AND SHOW WORK !!! NO BOTS PLS IM TIRED

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

It had four sides, ultimately making it a quadrilateral. Plot all four lines, and it could be a square, rectangle, rhombus, trapezoid, parallelogram, and kite.

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the two shorter sides of a triangle are the same length. the length of the longer side is 5 m longer than each of the shorter si
STatiana [176]
Let the length of the shorter sides be x, then
Perimeter = x + x + x + 5
29 = 3x + 5
3x = 29 - 5 = 24
x = 24/3 = 8

Therefore, the length of longest side is 8 + 5 = 13 m.
4 0
3 years ago
Read 2 more answers
Given that 3^-n=0.2<br> Find the value of (3^n)^2
dybincka [34]

Step-by-step explanation:

3^-n=0.2

1/3^n=0.2

1=0.2(3^n)

3^n=1/0.2

3^n=5

(3^n)²=5²

(3^n)²=25

7 0
3 years ago
A window is in the form of a rectangle capped by a semicircle. The width of the rectangular portion is equal to the diameter of
xxTIMURxx [149]

Answer:

The answer is below

Step-by-step explanation:

Let x be the diameter of the semicircle. radius = x/2

The window is a combination of a rectangle and semicircle.

Width of window = diameter = x, let length of the window = y.

Perimeter of semicircle = πr = πx/2

Perimeter of window = x + y + y + πx/2

20 = x + 2y + πx/2

2y + x + πx/2 = 20

2y = 20 - x(1 - π/2)

y = 10 - x(1 - π/2)/2

Area of semicircle = (1/2)πr² = (1/2)π(x/2)²

Area of window = xy + (1/2)π(x/2)²

A = x(10 - x(1 - π/2)/2) + πx²/8

A = 10x - x² - πx²/4 + πx²/8

A = 10x - x² - πx²/8

The maximum area is at dA / dx = 0

dA / dx = 10 - 2x - 2πx/8

0 = 10 - 2x - πx / 4

2x + πx / 4 = 10

2.785x = 10

x = 3.59 feet

Maximum area = 10x - x² - πx²/8 = 10(3.59) - 3.59² - π(3.59²) / 8

Maximum area = 17.95 feet²

3 0
3 years ago
Cube of the number -13/15
Ivan

Answer:

-\frac{2197}{3375}\\\mathrm{Decimal:\quad }\:-0.65096

Step-by-step explanation:

-\left(\frac{13}{15}\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}\\\left(\frac{13}{15}\right)^3=\frac{13^3}{15^3}\\=-\frac{13^3}{15^3}\\13^3=2197\\=-\frac{2197}{15^3}\\15^3=3375\\=-\frac{2197}{3375}

7 0
3 years ago
Read 2 more answers
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a stan
IgorLugansk [536]

Answer:

10.93% probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 3.02, \sigma = 0.29, n = 20, s = \frac{0.29}{\sqrt{20}} = 0.0648

Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.

This is 1 subtracted by the palue of Z when X = 3.10. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 3.02}{0.0648}

Z = 1.23

Z = 1.23 has a pvalue of 0.8907

1 - 0.8907 = 0.1093

10.93% probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.

5 0
4 years ago
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