A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop y of Midsummer’s Night Dream. In how many distinct arrangements can these ten books be put in order on a shelf?
1 answer:
Answer:
The number of distinct arrangements is <em>12600 </em><em>.</em>
Step-by-step explanation:
This is a permutation type of question and therefore the number of distinguishable permutations is:
n!/(n₁! n₂! n₃! ... nₓ!)
where
n₁, n₂, n₃ ... is the number of arrangements for each object n is the number of objects nₓ is the number of arrangements for the last object
In this case
n₁ is the identical copies of Hamlet n₂ is the identical copies of Macbeth n₃ is the identical copies of Romeo and Juliet nₓ = n₄ is the one copy of Midsummer's Night Dream
Therefore,
<em>Number of distinct arrangements = 10!/(4! × 3! × 2! × 1!)</em>
<em> = </em><em>12600 ways</em>
<em />
Thus, the number of distinct arrangements is <em>12600 </em><em>.</em>
You might be interested in
The answer is 4. All of the above
Answer:
A is right
B is acute
C is obtuse
D is right
Step-by-step explanation:
90 is right
anything under 90 is acute
over 90 obtuse
4/20 = x/20 +x 80 + 4x = 20x 80/16 = x 5 = x that being said. Is that your name???
The correct way of getting this answer with proof of simplifying the top to the multiplied amount and then subtracts that then simplify to double check
5 + a = p
brainliest please