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mezya [45]
3 years ago
5

A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop

y of Midsummer’s Night Dream. In how many distinct arrangements can these ten books be put in order on a shelf?
Mathematics
1 answer:
lesantik [10]3 years ago
4 0

Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

  • n₁, n₂, n₃ ... is the number of arrangements for each object
  • n is the number of objects
  • nₓ is the number of arrangements for the last object

In this case

  • n₁ is the identical copies of Hamlet
  • n₂ is the identical copies of Macbeth
  • n₃ is the identical copies of Romeo and Juliet
  • nₓ = n₄ is the one copy of Midsummer's Night Dream

Therefore,

<em>Number of distinct arrangements =  10!/(4! × 3! × 2! × 1!)</em>

<em>                                                         = </em><em>12600 ways</em>

<em />

Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

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There is 5/6 of an apple pie left from dinner. Tomorrow, Victor plans to eat 1/6 of the pie that was left. How much of the whole
Lady_Fox [76]
5/6 = 83% 
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83% of the apple pie was left from dinner. 
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Find out the answers to this
meriva

Answer:

\tan \theta = - \frac{1}{5} = - 0.2

\cos \theta = 0.98

\sin \theta = - 0.196

Step-by-step explanation:

It is given that \cot \theta = - 5 and \theta is in the fourth quadrant.

So, only \cos \theta will have positive value and \sin \theta, \tan \theta will have negative value.

Now, \cot \theta = - 5

⇒ \tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5} (Answer)

We know, that \sec^{2} \theta - \tan^{2} \theta = 1

⇒ \sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019

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⇒ \cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98 (Answer)

We know, that \csc^{2} \theta - \cot^{2} \theta = 1

⇒ \csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099

{Since, \sin \theta is negative then \csc \theta will also be negative}

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3 years ago
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