If A(t) is the amount of salt in the tank at time t, then A(0) = 50 g and
A'(t) = (1 g/L)*(3 L/min) - (A(t)/120 g/L)*(3 L/min)

Multiply both sides by
, so that the left side can be condensed as the derivative of a product:


Integrate both sides and solve for A(t).


Given that A(0) = 50 g, we have

so that the amount of salt in the tank at time t is

The strings cost $14. you would take the total cost ($72) and subtract the cost of the book ($16) and you would get $56. you would then divide 56 by the number of book bought (4 in all) and you would get $14.
Answer:
They were very angry about her helping the colonists.
Step-by-step explanation:
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Yes, 5 goes into 100 exactly 20 times because 5 multiplied by 20 is 100