Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
Answer:
x = 1
Step-by-step explanation:
In order to solve the given problem, we should have the knowledge of the following property.
- Measure of the tangents drawn from external points to a circle are equal.
46x - 1 = 45x
46 x - 45x = 1
x = 1
Answer:
1/25 ; 3/20 ; 3/50
Step-by-step explanation:
Total number of stickers :
(10 + 15 + 25) = 50 stickers
Probability = required outcome / Total possible outcomes
a. Selecting blue and blue stickers
P(First blue) = 10/50 = 1/5
P(second blue) = 10/50 = 1/5
1/5 * 1/5 = 1 / 25
b. Selecting one red sticker and then one orange sticker
P(First red) = 15/50 = 3/10
P(second orange) = 25/50 = 1/2
3/10 * 1/2 = 3 /20
Selecting one red sticker and then one blue sticker
P(First red) = 15/50 = 3/10
P(second blue) = 10/50 = 1/5
3/10 * 1/5 = 3 / 50
Respuesta:
La proporción común del término puede ser 1/5
Explicación paso a paso:
La fórmula para calcular la suma al infinito de una secuencia geométrica se expresa como:
Sinfty = a / 1-r
Dado
Sinfty = 5
Primer término a = 4
Requerido
Razón común r
Sustituir
5 = 4/1-r
5 (1-r) = 4
5-5r = 4
-5r = 4-5
-5r = -1
r = 1/5
Esto significa que la razón común debe ser 1/5 para que la suma hasta el infinito sea 5
Just use y2-y2/x2-x1
so
1+5 (because subtracting a negative is the same as adding a positive)
4-2
6/2
or 3/1 which is the same as 3
