I think it'd be better if you gave us some sort of diagram with it?
Answer:
![W \le 6](https://tex.z-dn.net/?f=W%20%5Cle%206)
Step-by-step explanation:
Given
![Area = 60ft^2\ (max)](https://tex.z-dn.net/?f=Area%20%3D%2060ft%5E2%5C%20%28max%29)
![Length = 10ft](https://tex.z-dn.net/?f=Length%20%3D%2010ft)
Required
Represent the width as an inequality
First, we represent the area as an inequality.
![Area = 60ft^2\ (max)](https://tex.z-dn.net/?f=Area%20%3D%2060ft%5E2%5C%20%28max%29)
max as used above means less than or equal to.
So, we have:
![Area \le 60](https://tex.z-dn.net/?f=Area%20%5Cle%2060)
The area of a rectangle is:
![Area = L * W](https://tex.z-dn.net/?f=Area%20%3D%20L%20%2A%20W)
So, we have:
![L * W \le 60](https://tex.z-dn.net/?f=L%20%2A%20W%20%5Cle%2060)
Substitute 10 for L
![10 * W \le 60](https://tex.z-dn.net/?f=10%20%2A%20W%20%5Cle%2060)
Divide both sides by 10
![\frac{10 * W}{10} \le \frac{60}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B10%20%2A%20W%7D%7B10%7D%20%5Cle%20%5Cfrac%7B60%7D%7B10%7D)
![W \le \frac{60}{10}](https://tex.z-dn.net/?f=W%20%5Cle%20%5Cfrac%7B60%7D%7B10%7D)
![W \le 6](https://tex.z-dn.net/?f=W%20%5Cle%206)
Step-by-step explanation:
By arc sum Postulate of a circle:
2 x + 3x + 4x = 360°
9x = 360°
x = 360°/9
x = 40°
3x = 3* 40° = 120°
By inscribed angle theorem:
By tangent secant theorem:
Since, measure of central angle is equal to the measure of its corresponding minor arc.
By angle sum Postulate of a triangle:
Answer:
it could either be n15
15n
because a number multiplied by 5 is
n15
but in mathematics a number comes before a letter when writing a mathematical expression