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2 years ago

Help please du today thanks u r worth it

Mathematics

1 answer:

attashe74 [19]2 years ago

4 0

I’m pretty sure it’s either C or D

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Select the action you would use to solve 4x = 16. Then select the property

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Since you are trying to find x, you have to divide both sides by 4 to isolate x and get your answer.

3 0

3 years ago

Multiply: x (x^2+2x+4) and -2 (x^2+2x+4) Combine like terms. Final Answer:

natulia [17]

Answer:

x^3-8

Step-by-step explanation:

x^3+2x^2+4x + -2x^2-4x-8

+2x^2 and -2x^2 cancel out

+4x and -4x cancel out

5 0

3 years ago

2x+3y=12 find four solutions

solong [7]

Answer:

1. x=3,y=2

2.x=0,y=4

3.x=-3,y=6

4.x=6,y=0

Step-by-step explanation:

x=3, y=2

2(3)+3(2)=6+6=12

x=0, y=4

2(0)+3(4)=0+12=12

x=-3, y=6

2(-3)+3(6)=-6+18=12

x=6,y=0

2(6)+3(0)=12+0=12. Hope this helps!

5 0

3 years ago

What are the solutions for x when y is equal to 0 in the following quadratic

Scrat [10]

Answer: Option C

Step-by-step explanation:

Given the quadratic equation $y = x^2 - 13x$ , substitute $y=0$ :

$0 = x^2 - 13x$

In this case, to find the solutions of the given quadratic equation, you must factor out the variable "x". Then:

$0=x(x-13)$

Therefore, you get that the solutions of this equation are the following:

$x=0\\\\\\x-13=0\\x=13$

Then, the answer is:

$x = 0\ or\ x = 13$

This matches with the option C.

5 0

3 years ago

I dont understand this

Westkost [7]

Answer:

$\dfrac{1}{2x(x-1)}$

Step-by-step explanation:

Given

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)$

Consider the numerator:

$x^2+2x+1=(x+1)^2$

Consider the denominator:

$x^2-1=(x-1)(x+1)$

Hence, the fraction becomes

$\dfrac{(x+1)^2}{(x-1)(x+1)}=\dfrac{x+1}{x-1}$

Consider the expression in brackets:

$2x^2+2x=2x(x+1)$

Divide:

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)=\dfrac{x+1}{x-1}\div 2x(x+1)=\dfrac{x+1}{x-1}\times \dfrac{1}{2x(x+1)}=\dfrac{1}{2x(x-1)}$

4 0

3 years ago