Question

Differentiate e="y = 3x {}^{3} + 8x - 7" alt="y = 3x {}^{3} + 8x - 7" align="absmiddle" class="latex-formula">



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Answer 1

Answer:

y=9x^2 + 8

Step-by-step explanation:

using the power rule, we will differentiate each term separately

d/dx of 3x^3 = (3)(3)x^(3-1) = 9x^2

d/dx of 8x = 8x^(1-1) = 8

d/dx of -7 = 0

combining them we get the derivative which is y = 9x^2 + 8

Answer 2

Answer:

9x² + 8

Step-by-step explanation:

The given function to us is ,

$\implies y = 3x {}^{3} + 8x - 7$

And we need to differentiate the given function with respect to x . Taking the given function and differenciating wrt x , we have

$\implies y = 3x^3 + 8x - 7$

Recall that , the derivative of constant is 0 . Therefore ,

$\implies \dfrac{dy }{dx}= \dfrac{d}{dx}(3x^3 + 8x - 7) \\\\\implies\dfrac{dy }{dx}= \dfrac{d}{dx}(3x^3)+\dfrac{d}{dx}(8x) + 0 \\\\\implies\dfrac{dy }{dx}= 3\times 3 . x^{3-1} + 8\times 1 . x^{1-1} \\\\\implies\underline{\underline{\dfrac{dy }{dx}= 9x^2+8}}$

Hence the derivative of given function is 9x² + 8 .