10 students per gender:
Boys: <span>four Xs over five and one X over zero, two, three, four, ten, and twelve.
5, 5, 5, 5, 0, 2, 3, 4, 10, 12 </span>→ 0, 2, 3, 4, 5, 5, 5, 5, 10, 12<span>
mean: 5.1
range: 12
</span><span>Girls: three Xs above eight, two Xs above three and four, and one X above two, six and seven.
8, 8, 8, 3, 3, 4, 4, 2, 6, 7 </span>→ 2, 3, 3, 4, 4, 6, 7, 8, 8, 8
<span>mean: 5.3
range: 6
The boys have the higher range while the girls have the higher mean value.
</span><span>
</span>
Answer:
The conditions necessary for the analysis are met.
The probability the newspaper’s sample will lead them to predict defeat is 0.7881
Step-by-step explanation:
We are given;
population proportion; μ = 52% = 0.52
Sample size;n = 400
The conditions are;
10% conditon: sample size is less than 10% of the population size
Success or failure condition; np = 400 x 0.52 = 208 and n(1 - p) = 400(1 - 0.52) = 192.
Both values are greater than 10
Randomization condition; we assume that the voters were randomly selected.
So the conditions are met.
Now, the standard deviation is gotten from;
σ = √((p(1 - p)/n)
where;
p is the population proportion
n is the sample size
σ is standard deviation
Thus;
σ = √((0.52(1 - 0.52)/400)
σ = √((0.52(0.48)/400)
σ = 0.025
Now to find the z-value, we'll use;
P(p^ > 0.5) = P(z > (x - μ)/σ)
Thus;
P(p^ > 0.5) = P(z > (0.5 - 0.52)/0.025)
This gives;
P(p^ > 0.5) = P(z > - 0.8)
This gives;
P(p^ > 0.5) = 1 - P(z < -0.8)
From the table attached we have a z value of 0.21186
Thus;
P(p^ > 0.5) = 1 - 0.21186 = 0.7881
Thus, the probability the newspaper’s sample will lead them to predict defeat is 0.7871
One and fifty onehundredths