49x^2 - 9 = 0
As there is no x term, we can pretty much guess we have a situation where we factlrise by something known aa difference of two squares, so to factorise it:
49 = 7^2
9 = 3^2
x^2 = (x)^2
so...
(7x - 3)(7x + 3) = 0
7x - 3 = 0 7x + 3 = 0
x = 3/7 x = -3/7
Answer:
The radius is 9.0 units
Step-by-step explanation:
we know that
In the right triangle of the figure ABC
Applying the Pythagorean Theorem
substitute the given values
solve for AB
Remember the the side AB of right triangle represent the radius of the circle
therefore
The radius is 9.0 units
A cross-section <span>is the intersection of a solid and a plane.
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The actual inverse function is:
And the domain is [0, ∞).
<h3>
Where is the mistake?</h3>
Remember that for a given function f(x) with a domain D and a range R.
For the inverse function, f⁻¹(x) the domain is R and the range is D.
Here, for the given function the domain is x ≥ 3 and the range is [0, ∞).
Then for the inverse function, which is:
(to check this, you must have that):
The domain will be [0, ∞) and the range x ≥ 3
If you want to learn more about inverse functions:
brainly.com/question/14391067
#SPJ1
Answer:
Given f(-2)
= -5 -7(-2)
= -5+14
= 9
Thus f(-2) of f(x)= 5-7x is 9