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bezimeni [28]
3 years ago
7

Divide until it terminates

Mathematics
1 answer:
stich3 [128]3 years ago
7 0
6.4÷30 points 08 equals 0.2127 Hope it helps!! :)
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Describe the graph of a linear equation written in the form Ax + By = C when C=0.
Zinaida [17]

Answer:

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Step-by-step explanation:

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5 0
2 years ago
Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

W(-1, 1) = (x_1, y_1)

X(1, 2) = (x_2, y_2)

Plug in the values

WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}

WX = \sqrt{(2)^2 + (1)^2}

WX = \sqrt{4 + 1}

WX = \sqrt{5}

WX = 2.24

✔️Distance between X(1, 2) and Y(2, -4)

Let,

X(1, 2) = (x_1, y_1)

Y(2, -4) = (x_2, y_2)

Plug in the values

XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}

XY = \sqrt{(1)^2 + (-6)^2}

XY = \sqrt{1 + 36}

XY = \sqrt{37}

XY = 6.08

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

Y(2, -4) = (x_1, y_1)

Z(-2, -1) = (x_2, y_2)

Plug in the values

YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}

YZ = \sqrt{(-4)^2 + (3)^2}

YZ = \sqrt{16 + 9}

YZ = \sqrt{25}

YZ = 5

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

Z(-2, -1) = (x_1, y_1)

W(-1, 1) = (x_2, y_2)

Plug in the values

ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}

ZW = \sqrt{(1)^2 + (2)^2}

ZW = \sqrt{1 + 4}

ZW = \sqrt{5}

ZW = 2.24

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0
3 years ago
Which ordered pair represents the y-intercept of the graph of the equation y = -3x - 9?
german
The y-intercept is the point where the graph crosses the y-axis. It is found by setting x=0. For your equation, that makes the x-term vanish and only the constant remains. The ordered pair is ...
  (x, y) = (0, -9)

4 0
3 years ago
Show all work to identify the asymptotes and end behavior of the function f(x)= 5x/x-25.
jeyben [28]

Considering the given function and the asymptote concept, we have that:

  • The vertical asymptote is of x = 25.
  • The horizontal asymptote is of y = 5.
  • The end behavior is that as x \rightarrow \infty, f(x) \rightarrow 5.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity. Hence it also gives the end behavior of the function.

In this problem, the function is:

f(x) = \frac{5x}{x - 25}.

The vertical asymptote is found as follows:

x - 25 = 0 -> x = 25.

The horizontal asymptote is found as follows:

y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = \lim_{x \rightarrow \infty} 5 = 5.

Hence the end behavior is that as x \rightarrow \infty, f(x) \rightarrow 5.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

3 0
2 years ago
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