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3 years ago

What's 1.51 in word form

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

7 0

One and fifty onehundredths

Alex787 [66]3 years ago

5 0

One point five one

if i understood your question right that might be the answer

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What is the sum of the series? Write in expanded form making sure to show all steps used to find the sum

pantera1 [17]

Answer:

-16

Step-by-step explanation:

k = 3

-2(3) + 5 = -1

k = 4

-2(4) + 5 = -3

k = 5

-2(5) + 5 = -5

k = 6

-2(6) + 5 = -7

(-1) + (-3) + (-5) + (-7)

= -16

3 0

3 years ago

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Lydia's teacher wants her class to take note of the gas prices around town and round them all to the nearest whole number. Lydia

Dima020 [189]

3.41, due to it being below .50

6 0

3 years ago

|4x-9|=5x Does anybody know the answer to this ?

oksano4ka [1.4K]

|4x-9|=5x

subtract 4 to both sides

and that will give you

|-9|=x then the 9 turns positive because of the brackets

9=X

3 0

4 years ago

Place value of 2 in Decimal <br>137.5428

harina [27]

Answer:

0.002

Step-by-step explanation:

The explanation has been explained in the attached picture above.

6 0

3 years ago

Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le

Helen [10]

Answer: $\overline{AC}=$ 12.5

Step-by-step explanation: The triangle ABC and its altitude $\overline{BD}$ is represented in the figure below.

<u>Altitude</u> is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of $\overline{BD}$ , now we have two similar triangles, which means that ratios of corresponding sides are equal:

$\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}$

$\overline{BD}^{2}=\overline{BC}.\overline{AD}$ (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

$\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}$

$\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2}$ (2)

Substituting (2) into (1):

$\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}$

We want to find f, so:

$\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}$

$f=\frac{10^{2}-5^{2}}{10}$

f = 7.5

The length of $\overline{AC}$ is

$\overline{AC}=f+5$

$\overline{AC}=7.5+5$

$\overline{AC}=12.5$

The length of the hypotenuse of triangle ABC is 12.5 units.

5 0

3 years ago

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