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mihalych1998 [28]
3 years ago
9

What's 1.51 in word form

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0
One and fifty onehundredths
Alex787 [66]3 years ago
5 0
One point five one

if i understood your question right that might be the answer
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A parabola can be drawn given a focus of (-4, 4) and a directrix of y = –6. Write
AlexFokin [52]

Answer:

6y+2x

Step-by-step explanation:

A parabola can be drawn given a focus of (-4, 4) and a directrix of y = –6. Write

5 0
3 years ago
Prove Forall x elementof Z, x^2 - 5x - 1 is odd.
Diano4ka-milaya [45]

Answer with Step-by-step explanation:

Let Z be a set of integers

We have to prove that x^2-5x-1 is odd for all value of x \inZ.

There are two cases

1.When x is an odd integer number

2.when x is even integer number

1.When x is an odd integer  number

When x is positive odd integer

Then x^2  is positive odd number (because square of odd positive number is always positive an odd number )

5x is also odd number

-5x -1 = -even number

Suppose x=3

Then -15-1=-16

Odd number - even number=Odd number

Hence ,x^2-5x-1 is an odd number .

When x is negative odd number

Then  x square is positive odd number  and 5x is negative odd term term

Therefore,odd number + odd number -1=Even  number -1=Odd number

Hence x^2-5x-1 is an odd number.

2.When  x is an even number

When x is positive even number

x square is positive even number  and 5x is positive even number

Even number -Even number -1 =Even number -odd number =Odd number

Suppose x=4

x^2-5x-1=16-20-1=-5=Odd number

When x is negative even number

Then x square is positive even number  and 5x is negative even number

x^2-5x-1=Even number +Even number -1=Even number -1=Odd number

Hence, for all elements of Zx^2-5x-1is odd.

7 0
3 years ago
In triangle ABC, AB = 11 cm, BC = 9 cm and CA = 10 cm.<br> Find the area of triangle ABC.
max2010maxim [7]

Answer:

Area = 42.43 square cm

Step-by-step explanation:

Using Heron's Formula :

 Area = \sqrt{s\times (s-a) \times (s-b) \times(s -c)} \ , \ where  \ s \ =\ \frac{a+ b+ c}{2}

<em><u>Find Area :</u></em>

<em><u></u></em>

s = \frac{11 + 9 + 10 }{2} = \frac{30}{2} = 15

Area = \sqrt{15 \times ( 15 - 11 ) \times { (15 - 9 ) \times ( 15 -10)}\\\\

      = \sqrt{15 \times 4 \times 6 \times 5}\\\\=\sqrt{1800}

      = 42 . 43 \ cm^2

7 0
3 years ago
198round to the nearest tens and hundreds
Xelga [282]
198 round to the nearest hundreds is 200
198 round to the nearest tens is 200 too
8 0
3 years ago
Can someone help me with this and show their work and how they found the answer?
Semenov [28]

Answer:

2kg

Step-by-step explanation:

Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be

H = 2/3 * R

= 2R/3

Given that the 3 bricks weigh 5kg in total then,

2R/3 + R = 5

Multiply through the equation by 3

2R + 3R = 15

5R = 15

Divide both sides by 5

R = 15/5

= 3

The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs

= 2 * 3/3

= 2kg

4 0
3 years ago
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