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inysia [295]
3 years ago
6

Find the surface area Please explain

Mathematics
2 answers:
earnstyle [38]3 years ago
6 0

Answer:

Given

=>A Trapezoidal Prism

To Find

=>The surface area

Solution:

=>

<em><u>The surface area S = 2. A Base + Lateral Surface Area</u></em>

Atrapezoid = A Base

h (a+b)

L Lateral Surface Area = the sum of the areas of each surface around the Base.

L = al + cl + bl + dl

Substitute each piece into the equation:

h S = 2 (a + b) + al + cl + bl + dl 2

Simplify:

S = h(a + b) + al + cl + bl + dl =

Distribute and Rearrange

: S = ha + hb + al + cl + bl + dl

<em><u>S = a(h + </u></em><em><u>l</u></em><em><u>) + b(h + </u></em><em><u>l</u></em><em><u>) + cl + dl</u></em>

Here,

a =4yd

h = 4.6yd

b =8yd

c= 5yd

d=5yd

l=4yd

<em><u>INSERTING</u></em><em><u> </u></em><em><u>the </u></em><em><u>values </u></em><em><u>in </u></em><em><u>the </u></em><em><u>formula</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>S </u></em><em><u>=</u></em><em><u> </u></em><em><u>4</u></em><em><u>(</u></em><em><u>4</u></em><em><u>.</u></em><em><u>6</u></em><em><u>+</u></em><em><u>4</u></em><em><u>)</u></em><em><u>+</u></em><em><u>8</u></em><em><u>(</u></em><em><u>4</u></em><em><u>.</u></em><em><u>6</u></em><em><u>+</u></em><em><u>4</u></em><em><u>)</u></em><em><u>+</u></em><em><u>5</u></em><em><u>*</u></em><em><u>4</u></em><em><u>+</u></em><em><u>5</u></em><em><u>*</u></em><em><u>4</u></em>

<em><u>=</u></em><em><u>></u></em><em><u>S </u></em><em><u>=</u></em><em><u> </u></em><em><u>4</u></em><em><u>*</u></em><em><u>8</u></em><em><u>.</u></em><em><u>6</u></em><em><u>+</u></em><em><u> </u></em><em><u>8</u></em><em><u>*</u></em><em><u>8</u></em><em><u>.</u></em><em><u>6</u></em><em><u>+</u></em><em><u>2</u></em><em><u>0</u></em><em><u>+</u></em><em><u>2</u></em><em><u>0</u></em>

<em><u>=</u></em><em><u>></u></em><em><u>S </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>4</u></em><em><u>.</u></em><em><u>4</u></em><em><u>+</u></em><em><u>6</u></em><em><u>8</u></em><em><u>.</u></em><em><u>8</u></em><em><u>+</u></em><em><u>4</u></em><em><u>0</u></em>

<em><u>=</u></em><em><u>></u></em><em><u>S=</u></em><em><u>1</u></em><em><u>4</u></em><em><u>3</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>Cm </u></em><em><u>²</u></em>

<h2><em><u>Hence </u></em><em><u>,</u></em><em><u>(</u></em><em><u>a)</u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em><em><u>3</u></em><em><u>.</u></em><em><u>2</u></em><em><u>c</u></em><em><u>m</u></em><em><u>²</u></em><em><u> </u></em><em><u>is </u></em><em><u>the</u></em><em><u> correct</u></em><em><u> answer</u></em></h2>

Dmitriy789 [7]3 years ago
5 0

Step-by-step explanation:

There are two trapezium(s), area of 2:

= 2 [½ x (sum of || sides) x height]

= 2[½ x (4 + 8) x 4.6 ] [not clearly visible if it is 4.5 or 4.6]

= 55.2 yd²

Area of vertically tilted rectangles

1): area = 5 x 4 = 20 yd²

2): area = 5 x 4 = 20 yd²

Total area = 20 + 20 = 40 yd²

Area of horizontal rectangles:

1): area = 4 x 8 = 32 yd² [upper]

2): area = 4 x 4 = 16 yd² [lower]

Area of given surface = 55.2 + 40 + 32 + 16 = 143.2 yd²

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Answer:

Step-by-step explanation:

(7,6)    (-3,-1)

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Answer:

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7 0
2 years ago
Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

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y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

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3 years ago
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Alborosie

Answer:

£35,020

Step-by-step explanation:

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= £34000 + 0.03*£34000

= £34000 + £1,020

=£35,020

6 0
3 years ago
Read 2 more answers
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