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inysia [295]
3 years ago
6

Find the surface area Please explain

Mathematics
2 answers:
earnstyle [38]3 years ago
6 0

Answer:

Given

=>A Trapezoidal Prism

To Find

=>The surface area

Solution:

=>

<em><u>The surface area S = 2. A Base + Lateral Surface Area</u></em>

Atrapezoid = A Base

h (a+b)

L Lateral Surface Area = the sum of the areas of each surface around the Base.

L = al + cl + bl + dl

Substitute each piece into the equation:

h S = 2 (a + b) + al + cl + bl + dl 2

Simplify:

S = h(a + b) + al + cl + bl + dl =

Distribute and Rearrange

: S = ha + hb + al + cl + bl + dl

<em><u>S = a(h + </u></em><em><u>l</u></em><em><u>) + b(h + </u></em><em><u>l</u></em><em><u>) + cl + dl</u></em>

Here,

a =4yd

h = 4.6yd

b =8yd

c= 5yd

d=5yd

l=4yd

<em><u>INSERTING</u></em><em><u> </u></em><em><u>the </u></em><em><u>values </u></em><em><u>in </u></em><em><u>the </u></em><em><u>formula</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>S </u></em><em><u>=</u></em><em><u> </u></em><em><u>4</u></em><em><u>(</u></em><em><u>4</u></em><em><u>.</u></em><em><u>6</u></em><em><u>+</u></em><em><u>4</u></em><em><u>)</u></em><em><u>+</u></em><em><u>8</u></em><em><u>(</u></em><em><u>4</u></em><em><u>.</u></em><em><u>6</u></em><em><u>+</u></em><em><u>4</u></em><em><u>)</u></em><em><u>+</u></em><em><u>5</u></em><em><u>*</u></em><em><u>4</u></em><em><u>+</u></em><em><u>5</u></em><em><u>*</u></em><em><u>4</u></em>

<em><u>=</u></em><em><u>></u></em><em><u>S </u></em><em><u>=</u></em><em><u> </u></em><em><u>4</u></em><em><u>*</u></em><em><u>8</u></em><em><u>.</u></em><em><u>6</u></em><em><u>+</u></em><em><u> </u></em><em><u>8</u></em><em><u>*</u></em><em><u>8</u></em><em><u>.</u></em><em><u>6</u></em><em><u>+</u></em><em><u>2</u></em><em><u>0</u></em><em><u>+</u></em><em><u>2</u></em><em><u>0</u></em>

<em><u>=</u></em><em><u>></u></em><em><u>S </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>4</u></em><em><u>.</u></em><em><u>4</u></em><em><u>+</u></em><em><u>6</u></em><em><u>8</u></em><em><u>.</u></em><em><u>8</u></em><em><u>+</u></em><em><u>4</u></em><em><u>0</u></em>

<em><u>=</u></em><em><u>></u></em><em><u>S=</u></em><em><u>1</u></em><em><u>4</u></em><em><u>3</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>Cm </u></em><em><u>²</u></em>

<h2><em><u>Hence </u></em><em><u>,</u></em><em><u>(</u></em><em><u>a)</u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em><em><u>3</u></em><em><u>.</u></em><em><u>2</u></em><em><u>c</u></em><em><u>m</u></em><em><u>²</u></em><em><u> </u></em><em><u>is </u></em><em><u>the</u></em><em><u> correct</u></em><em><u> answer</u></em></h2>

Dmitriy789 [7]3 years ago
5 0

Step-by-step explanation:

There are two trapezium(s), area of 2:

= 2 [½ x (sum of || sides) x height]

= 2[½ x (4 + 8) x 4.6 ] [not clearly visible if it is 4.5 or 4.6]

= 55.2 yd²

Area of vertically tilted rectangles

1): area = 5 x 4 = 20 yd²

2): area = 5 x 4 = 20 yd²

Total area = 20 + 20 = 40 yd²

Area of horizontal rectangles:

1): area = 4 x 8 = 32 yd² [upper]

2): area = 4 x 4 = 16 yd² [lower]

Area of given surface = 55.2 + 40 + 32 + 16 = 143.2 yd²

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A summer camp is organizing a hike and needs to buy granola bars for the campers. The granola bars come in small boxes and large
Irina18 [472]

Answer:

The Answer is: There are 8 small boxes and 9 large boxes. See explanation below for variables and variable definitions.

Step-by-step explanation:

Let s = small boxes. Let b = large boxes.

s + b = 17

You can solve for s:

s = 17 - b

You can solve for b:

b = 17 - s

10 times the number of small boxes plus 24 times the number of large boxes is equal to 296 granola bars.

10s + 24b = 296

Substitute:

10(17 - b) + 24b = 296

170 - 10b + 24b = 296

14b = 296 - 170

14b =  126

b = 126 / 14 = 9 large boxes

Find the number of small boxes, s:

s = 17 - b = 17 - 9 = 8 small boxes

There are 8 small boxes and 9 large boxes.

Proof:

10(8) + 24(9) = 296

80 + 216 = 296

296 = 296

4 0
3 years ago
What is the area of the kite?
Alona [7]

Answer:

im not fully sure because im a 4th grader but 52 i think.

7 0
3 years ago
K is the midpoint of PQ, P has
Pachacha [2.7K]

Answer:

Coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q  (x_2,y_2)

We will use the formula of midpoint: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given midpoint K and x_1,y_1 the coordinates of P we need to find x_2,y_2 the coordinates of Q.

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\

Now, we can write

-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16

So, we get coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

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Shkiper50 [21]

Answer:

Step-by-step explanation:

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Out of the thirty
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Answer:

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