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Lady bird [3.3K]
3 years ago
12

ashton left his house and ran 4 miles east and then 3 miles north. he then took the diagonall path back home. if the burned 105

calories every mile thet he ran, how many total calories did he burn on his run
Mathematics
2 answers:
VikaD [51]3 years ago
8 0
First you find out the number of miles there is. For that, you use the following calculation:
4 square plus 3 square equals diagonal square.
which is
16 plus 9 equals diagonal square
so
root of 25 equals 5
So we add it all up: 4 plus 3 plus 5 equals 12
So he ran 12 miles altogether.
Then: 12 times 105 equals 1260 calories.
tatiyna3 years ago
3 0
1260 calories Ashton burned
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AlekseyPX
Y = mx + b
where m is the gradient (slope)
-4y = 11 - 8x
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The correct answer is A.
7 0
3 years ago
Evaluate 24. 5 PLS AND THANK YOU!!!
GREYUIT [131]

Answer:

80

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

2⁴ · 5

<u>Step 2: Evaluate</u>

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4 0
2 years ago
A financial advisor is analyzing a family's estate plan. The amount of money that the family has invested in different real esta
Pachacha [2.7K]

Answer:

The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.

The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.

It is provided that the family has invested in <em>n</em> = 10 different real estate properties.

Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

\mu_{\bar x}=\mu=\$225,000\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{50000}{\sqrt{10}}=15811.39

Now the lowest 80% of the amount invested can be represented as follows:

P(\bar X

The value of <em>z</em> is 0.84.

*Use a <em>z</em>-table.

Compute the value of the mean amount invested as follows:

\bar x=\mu_{\bar x}+z\cdot \sigma_{\bar x}

   =225000+(0.84\times 15811.39)\\\\=225000+13281.5676\\\\=238281.5676\\\\\approx 238281.57

Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

6 0
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