can be simplified as 5-9+7=-4+7=3
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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Let's use the slope formula!
m = y2 - y1 / (x2 - x1)
m = 6 + 7 / (-3 + 7) = 13/4
Answer:
The child can sell 15 cookies and 30 lemonade glasses, or 10 cookies and 40 glasses of lemonade, etc
Step-by-step explanation:
If the child wants to make $30 and gets $1 per cookie and $0.50 per lemonade glass, he could sell 15 cookies and 30 glasses, 10 cookies and 40 glasses, etc. He has to sell at least 5 cookies, though, as the lemonade is only worth $25.
Answer:
Step-by-step explanation:
Using I=PRT (interest= principal times rate times time) we can solve the problem
12800 times 0.15 (15%) =1920 then you multiply it by time and then you have your answer
