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PIT_PIT [208]
3 years ago
8

A scatterplot is shown on the graph below. Which of these could be the line of best fit? x = 100 y = 100 y = x – 100 y = x + 100

Mathematics
1 answer:
kkurt [141]3 years ago
6 0

Answer:

55 when y dived and subtracting

Step-by-step explanation:

djiiwwuwb skis wujw que wjsjs what s

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Find the midrange for the group of data items.<br> 2, 2, 5, 5, 8, 8, 10
elena55 [62]

Answer:

5

Step-by-step explanation:

Answer:5

Start striking off the numbers one from the left and then from the right continuously until you're left with a number in the middle

3 0
3 years ago
In a fruit survey, 300 children choose their favorite fruit out of apples, bananas and watermelon. 38% chose apples, 28% chose b
mojhsa [17]
34 percent chose watermelon i think
8 0
3 years ago
A patient is ordered 60 mg/kg/day of an antibiotic to be divided in 3 doses per day. The patient weighs 60 kg. How many mg of dr
Fudgin [204]

Answer:

3600 mg of drug per day.

\text{The amount of drug per dosage}=\text{1200 mg}

Step-by-step explanation:

We have been given that a patient is ordered 60 mg/kg/day of an antibiotic.

Since the weight of the patient is 60 kg, so the dosage of drug per day would be 60 mg times 60.

\text{The dosage of drug per day}=\frac{\text{60 mg}}{\text{ kg}}\times 60\text{ kg}

\text{The dosage of drug per day}=\text{60 mg}\times 60

\text{The dosage of drug per day}=\text{3600 mg}

Therefore, the patient should receive 3600 mg of drug per day.

Since the patient gets 3 doses per day, so dosage of drug per dosage would be amount of drug per day divided by 3.

\text{The amount of drug per dosage}=\frac{\text{3600 mg}}{3}

\text{The amount of drug per dosage}=\text{1200 mg}

Therefore, the amount of drug per dosage would be 1200 mg.

3 0
4 years ago
If the perimeter of A rectangle is 70" in and the length is 11" in more than its width find the area of the rectangle
steposvetlana [31]
First, write an equation system based on the problem
An equation for "the perimeter of a rectangle is 70 in" can be written as following
∴ 2l + 2w = 70  <em>(first equation)</em>
An equation for "the length is 11 in more than its width" can be written as following
∴ l = w + 11 <em>(second equation)</em>

Second, solve the equation by substitution method o find the dimension of the rectangle.
Substitute/plug l as (w+11) into the first equation
2l + 2w = 70
2(w + 11) + 2w = 70
2w + 22 + 2w = 70
4w + 22 = 70
4w = 70 - 22
4w = 48
w = 48/4
w = 12
The width of the rectangle is 12 in

Substitute w with 12 to the second equation
l = w + 11
l = 12 + 11
l = 23
The length of the rectangle is 23 in

Third, find the area of the rectangle
a = l × w
a = 23 × 12
a = 276
The area of the rectangle is 276 in²
4 0
3 years ago
How do I solve -3(x-1)+8(x-3)=6x+7-5x
katrin [286]

Answer:

X=7

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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