Answer:
Fifth graders= 93 shirts
Sixth graders= 156 shirts
Teachers= 51 shirts
Step-by-step explanation:
31% of 300 is 93
52% of 300 is 156
The total number of shirts sold to fifth graders and sixth graders is:
156+93= 249
The number of shirts sold to teachers is:
300-249= 51
Answer:
<h3>3/20*200</h3>
=5*3
=15%
the percentage of the number is 15%
The cost of a senior citizen ticket is $15 and the cost of a student ticket is $12.
How did I get this?
We know that 6 citizen tickets and 7 student stickers sold for $174 the first day. And 10 citizen tickets and 14 student tickets sold for $318 the second day.
1. create two equations out of this: C= citizen cost per ticket and S = student cost per ticket.
6C + 7S = $174
10C + 14S = $318
2. Use process of elimination. Multiply the first equation by 2 because we want two variables to cancel out.
-12C - 14S = -$348
10C + 14S = $318
Combine like terms.
-2C = $30
Divide by -2 on both sides. The left side cancels out.
C = $30/-2
C = -$15 (In this case the negative doesn't matter)
C = $15 (cost of senior citizen ticket)
Plug the value of C into any of the two equations so we can get the value of S.
6($15) + 7S = $174
Distribute the 6 into the parenthesis.
$90 + 7S = $174
Subtract both sides by $90 and the left side will cancel out.
7S = $84
Divide both sides by 7.
S = $12
Student ticket: $12
Senior citizen ticket: $15
This is a hexagonal prism: Volume = Area of Base (hexagon) x Height:
There are 6 equal equilateral triangles in a hexagone.
The apothem (or altitude of each triangle) = side x (√3)/2 =12(√3)/2 = 6√3
Area of ONE equilateral triangle = (side x altitude)/2:
Area of ONE equilateral triangle = (12 x 6√3)/2 = 36√3 ft²
Area of the SIX equilateral triangles = 36√3 x 6 = 216√3 ft²
VOLUME = BASE X HEIGHT = 216√3 x 15 = 3240√3 ft³
OR VOLUME = 5612 ft³
Answer:
(2, 2 )
Step-by-step explanation:
To find a solution, choose any value for x, substitute into the equation and solve for y.
Choose x = 2, then
- 2 - 4y = - 10 ( add 2 to both sides )
- 4y = - 8 ( divide both sides by - 4 )
y = 2
Thus (2, 2 ) is a solution to the equation