3 years ago

Please answer for 20 points

Mathematics

2 answers:

Vesnalui [34]3 years ago

7 0

Answer:

Step-by-step explanation:

whenever you see a (as in ax^2 + bx+c) as a number other than 1, you should see if you can factor that out

2(6x^2 -x -1)

= 2(3x+1) (2x-1)

lora16 [44]3 years ago

6 0

Answer:

2$3x+1)(2x-1$

Step-by-step explanation:

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If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find ƒ(-1) + 5g(-3). -40 -38 7

EastWind [94]

$f(x) = x^2 + 1 \\ 
g(x) = 3x + 1$

You can do this in parts.
$f(-1) = (-1)^2 + 1 = 1 + 1 = 2$
g(-3) = 3(-3) + 1 = -9 + 1 = -8
So, 5g(-3) = 5(-8) = -40.
So f(-1) + 5g(-3) = 2 - 40 = -38

Or you can do this as one big chunk.
f(-1) + 5g(-3)
$=[(-1)^2+1] + 5[3(-3) + 1] \\
= (2) + 5(-9 + 1) \\
= 2 + 5(-8) \\
= 2 - 40 \\ = -38$