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3 years ago

Please answer for 20 points

Mathematics

2 answers:

Vesnalui [34]3 years ago

7 0

Answer:

Step-by-step explanation:

whenever you see a (as in ax^2 + bx+c) as a number other than 1, you should see if you can factor that out

2(6x^2 -x -1)

= 2(3x+1) (2x-1)

lora16 [44]3 years ago

6 0

Answer:

2$3x+1)(2x-1$

Step-by-step explanation:

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What is the answer and what should I write for my explanation? Can you please show me all the work?

Stells [14]

Answer:

sorry i didn't get it

Step-by-step explanation:

7 0

3 years ago

Need help please assist me find the area of a regular hexagon

garri49 [273]

Answer:

The area of the regular hexagon is $166.3\ units^{2}$

Step-by-step explanation:

we know that

The area of a regular hexagon can be divided into 6 equilateral triangles

step 1

Find the area of one equilateral triangle

$A=\frac{1}{2}(b)(h)$

we have

$b=r=8\ units$

$h=4\sqrt{3}\ units$ ----> is the apothem

substitute

$A=\frac{1}{2}(8)(4\sqrt{3})$

$A=16\sqrt{3}\ units^{2}$

step 2

Find the area of 6 equilateral triangles

$A=(6)16\sqrt{3}=96\sqrt{3}=166.3\ units^{2}$

7 0

3 years ago

Write each of the following expressions without using absolute value: |z−6|−|z−5|, if z<5

abruzzese [7]

Answer:

The answer is 1.

Step-by-step explanation:

Given the expression:

$|z-6|-|z-5|,\ if\ z$

To find:

The expression without absolute value.

Solution:

First of all, let us learn about the absolute value function:

$y = f(x) = |x| =\left \{ {{x\ if\ x>0} \atop {-x\ if\ x$

i.e. value is x if x is positive

value is -x if x is negative

Here the given expression contains two absolute value functions:

$|z-6|$ and $|z-5|$

Using the definition of absolute value function as per above definition.

$|z-5| =\left \{ {{(z-5)\ if\ z>5} \atop {-(z-5)\ if\ z$

$|z-6| =\left \{ {{(z-6)\ if\ z>6} \atop {-(z-6)\ if\ z$

Now, it is given that z < 5 that means z will also be lesser than 6 i.e. z < 6

So, given expression $|z-6|-|z-5|,\ if\ z$ will be equivalent to :

$-(z-6) - (-(z-5))\\\Rightarrow -z+6 +z-5 = \bold{1}$

So, the expression is equivalent to 1.

6 0

3 years ago

12x - 84 = 4x + 12. What does X equal?

Vesnalui [34]

Answer:

Step-by-step explanation:

To solve the problem, you have to leave the x alone,

To do so, you have to add 84 on each side

12x = 4x + 96

Then, subtract 4x on each side,

8x = 96

Then divide each side by 8, so

x = 12

Hope it helps!!

Let me know if I'm wrong or you need help on anything else!!

Also, if you're okay with it, can you plz make be brainliest?

8 0

3 years ago

Read 2 more answers

Two cars start out together from the same place. they travel in opposite directions, with one of them traveling 5 miles per hou

Mashutka [201]

Annotation
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.

One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5 (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
$\boxed{\boxed{ v_{1}=68mph} }$
$\boxed{\boxed{ v_{2}=63mph} }$

7 0

3 years ago