![\bf \qquad \textit{Compounding Continuously Earned Amount}\\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$1740\\ r=rate\to 12\%\to \frac{12}{100}\to &0.12\\ t=years\to &5 \end{cases} \\\\\\ A=1740\cdot e^{0.12\cdot 5}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BCompounding%20Continuously%20Earned%20Amount%7D%5C%5C%5C%5C%0AA%3DPe%5E%7Brt%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%241740%5C%5C%0Ar%3Drate%5Cto%2012%5C%25%5Cto%20%5Cfrac%7B12%7D%7B100%7D%5Cto%20%260.12%5C%5C%0At%3Dyears%5Cto%20%265%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D1740%5Ccdot%20e%5E%7B0.12%5Ccdot%205%7D)
bear in mind that the continuously compounding interest is just that, a daily compounding cycle, taking a year as 365days.
Solution: We are given:
![\mu=15, \sigma=5](https://tex.z-dn.net/?f=%5Cmu%3D15%2C%20%5Csigma%3D5)
Using the empirical rule, we have:
covers 68% of data.
Also the percentage of values below mean = Percentage of values above mean = 50%
Now, let's find the z score for x=20
![z=\frac{20-15}{5}=1](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B20-15%7D%7B5%7D%3D1)
Therefore, the percentage of values greater than 1 standard deviation above mean ![50\% - \frac{68\%}{2} =50\%-34\%=16%](https://tex.z-dn.net/?f=50%5C%25%20-%20%5Cfrac%7B68%5C%25%7D%7B2%7D%20%3D50%5C%25-34%5C%25%3D16%25)
Expected number of students = 16% of 100 = 16
Answer:
A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length
Step-by-step explanation:
Answer: The proportion of employees who either have MBAs or are managers are 0.58.
Step-by-step explanation:
Since we have given that
Probability of employees having managerial positions = 67%
Probability of employees having MBA degrees = 58%
Probability of managers having MBA degrees = 67%
So, using probability formulas, we get that
![P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=0.67+0.58-0.67\\\\P(A\cup B)=0.58](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%3DP%28A%29%2BP%28B%29-P%28A%5Ccap%20B%29%5C%5C%5C%5CP%28A%5Ccup%20B%29%3D0.67%2B0.58-0.67%5C%5C%5C%5CP%28A%5Ccup%20B%29%3D0.58)
Hence, the proportion of employees who either have MBAs or are managers are 0.58.
Answer:
6+12b
Step-by-step explanation:
i took a test with this question and got it right