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3 years ago

HELP worth 10 points!!

Mathematics

1 answer:

BaLLatris [955]3 years ago

4 0

Answer:

The answer is D 11/35

Step-by-step explanation:

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Wich is bigger 1.320. 1.302 < > =

elena-14-01-66 [18.8K]

1.320 >1.302 or 1.302<1.320

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3 years ago

Which of the following inequalities is graphed below?

nikklg [1K]

A : y is greater than or equal to 4x plus two

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3 years ago

Matthew Casertano and Fox Chyatte make a series of bets. In each bet, Matthew sets the stake (the amount he wins or loses) at ha

Olin [163]

Answer:

219/256 = 0.855

Step-by-step explanation:

He starts with $256.

After the first bet, he either has $128 or $512.

After the second bet, he either has $64, $256, or $1024.

Repeating this pattern, the amount after n bets and r wins is:

A = 256 (½)ⁿ⁻ʳ (2)ʳ

And the number of ways A can be achieved is:

N = nCr

We're given that n = 8.

A = 256 (½)⁸⁻ʳ (2)ʳ

If r = 0, A = 1 and N = 1.

If r = 1, A = 4 and N = 8.

If r = 2, A = 16 and N = 28.

If r > 2, A > 50. The sum of N for all r is 2⁸ = 256.

Of the 256 possible combinations, 1+8+28 = 37 result in less than $50, so 219 result in more than $50.

So the probability is 219/256 = 0.855.

5 0

3 years ago

Barron's reported that the average number of weeks an individual is unemployed is 18.5 weeks. Assume that for the population of

Ket [755]

Answer:

A) The sampling distribution for a sample size n=50 has a mean of 18.5 weeks and a standard deviation of 0.849.

B) P = 0.7616

C) P = 0.4441

Step-by-step explanation:

We assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 6 weeks.

A) We take a sample of size n=50.

The mean of the sampling distribution is equal to the population mean:

$\mu_s=\mu=18.5$

The standard deviation of the sampling distribution is:

$\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{50}}=0.849$

B) We have to calculate the probability that the sampling distribution gives a value between one week from the mean. That is between 17.5 and 19.5 weeks.

We can calculate this with the z-scores:

$z_1=\dfrac{X_1-\mu}{\sigma/\sqrt{n}}=\dfrac{17.5-18.5}{6/\sqrt{50}}=\dfrac{-1}{0.8485}=-1.179\\\\\\z_2=\dfrac{X_2-\mu}{\sigma/\sqrt{n}}=\dfrac{19.5-18.5}{6/\sqrt{50}}=\dfrac{1}{0.8485}=1.179$