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jasenka [17]
4 years ago
8

true of false. if the movement of a mass on a spring may be modeled with simple harmonic motion, then its frequency decreases wi

th time
Mathematics
2 answers:
brilliants [131]4 years ago
8 0

Answer:

False

Step-by-step explanation:

a pex

abruzzese [7]4 years ago
6 0

The statement “If the movement of a mass on a spring may be modeled with simple harmonic motion, then its frequency decreases with time” is false.

 

<span>In mechanics and physics, simple </span><span>harmonic motion </span>is a type of periodic motion<span> or oscillation </span><span>motion </span>where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement .

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P=2.50x+100

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3 years ago
Draw the graph for the equation by first finding at least two points on the line.<br> 2x-y=9
ELEN [110]

Answer:

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4 0
1 year ago
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xenn [34]

Answer:

Perpendicular bisector

Step-by-step explanation:

The construction is of a perpendicular bisector, because the line in bisected and the angle formed by the bisector is a right angle.

6 0
3 years ago
A subtending arc on a circle with a radius of 4.5 centimeters has an arc length of 8π. The measure of the angle subtended by the
dem82 [27]

Answer: 320°

Step-by-step explanation:

This is a circle geometry.

The arc length of the circle is given to be 8πcm and the radius is 4.5cm.

Now the length of an arc of a circle is

Arc length = πr0°/180° or 2πr0°/360°

To find the angle 0° subtend at the center we equate the arc length with the formula and solve for 0°.Now we go

πr0°/180 = 8π, convert to a simple linear equal and solve for the angle.

πr0° = 8π × 180

0°. = 8π × 180

-----------

π × r

= 8 × 180. 8 × 180

-------- or ---------

9/2. 4.5

= 8 × 180 × 2

------------

9

= 8 × 20 × 2

= 320°

or 8 × 180/4.5

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4 0
3 years ago
Suppose that each observation in a random sample of 100 fatal bicycle accidents in 2015 was classified according to the day of t
liraira [26]

Answer:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0:  proportion of fatal bicycle accidents in 2015 was the same for all days of the week

against the claim

Ha:  proportion of fatal bicycle accidents in 2015 was not the same for all days of the week

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (ni - npi)²/ npi

which has an approximate chi square distribution with ( n-1)=7-1=  6 d.f

4) The critical region is χ² ≥ χ² (0.05)6 = 12.59

5) Calculations:

χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28

χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]

χ²= 1/14.28[8.1364]

χ²= 0.569= 0.57

6) Conclusion:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week

6 0
3 years ago
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