Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be: 
miles/hour
and the <u>speed of Pratap against the current</u> will be: 
miles/hour.
Suppose, the rate of Pratap in still water is 
and the rate of current is 
.
So, the equations will be........
Adding equation (1) and (2) , we will get......
Now, plugging this 
into equation (1), we will get.....
Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
I think it’s 4 if the lines are going up by 2
Answer:
x=2.2
y=-3.4
Step-by-step explanation:
subtract the second from the first
-5x=-11
x=2=2
substituting by x in the first equation
so y=-3.4
Answer:
y = -7/3x + 10
Step-by-step explanation:
Step 1: Find the slope of the perpendicular line
Do this by taking the negative inverse of the first line
m = -7/3
Step 2: Find <em>b</em>
y = mx + b
y = -7/3x + b
3 = -7/3(3) + b
3 = -7 + b
b = 10
You should get y = -7/3x + 10 as your final answer.
Answer:
steps below
Step-by-step explanation:
BD⊥AC ∠ADB = ∠CDB = 90°
D is mid-point: AD = CD
BD = BD
ΔADB ≅ ΔCDB
AB = BC
