<span>3 = log(8) + log(x³) </span>
<span>When adding logs, you are multiplying the terms altogether. </span>
<span>3 = log(8x³) </span>
<span>Then, by log_a b = n ==> aⁿ = b: </span>
<span>10³ = 8x³ [Since the base is not given, I assume that the base is 10] </span>
<span>1000 = 8x³ </span>
<span>Finally, solve for x. </span>
<span>1000/8 = x³ </span>
<span>x³ = 125 </span>
<span>x = (125)^(1/3) . . .Set both sides to the power of 1/3. </span>
<span>x = 5 </span>
<span>Hence, x = 5. </span>
I am pretty sure that it's
A. 1
Answer:
The estimated Rabbit population by the year 2036 is 32,309 rabbits
Step-by-step explanation:
In this question, we are expected to use the exponential decay function to estimate population of rabbits in a certain year.
An exponential decay function refers to an equation that estimates the value of a parameter(dependent parameter) at a certain value of the independent parameter given that the independent parameter decreases at a certain constant rate.
Firstly, what we need to do is to write the decay function. To do this, we shall be representing the population by variable P, the rate by r , the number of years by t and the initial population by I
Mathematically, we have the decay function as;
P = I(1-r)^t
From the question, we identify these values as;
P = 144,000 : r = 7.2% = 7.2/100 = 0.072, I = 144,00 and t = 2036-2016 = 20 years
Let's plug these values;
P = 144,000(1-0.072)^20
P = 144,000(0.928)^20
P= 32,309
They can rent it for 7 hr. $20.60-$4.50=$16.10. $16.1 divided by $2.30= 7
