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UNO [17]
3 years ago
14

Need help with this question. Thank you

Mathematics
2 answers:
Natali [406]3 years ago
7 0
I think the answer is B.
V125BC [204]3 years ago
3 0
I think the answer is b
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What is 4 to the 7th power ?
bonufazy [111]
4^7=16,384 i  used a calulator

5 0
3 years ago
(-----×1/4)÷6×3/9 I need the step to this problem so that I explain to my grandson how he he gets the answer
lesya692 [45]

Answer:

-----×1/72

Step-by-step explanation:

The <em>order of operations</em> says do these operations in order left to right. Please note that ÷ means the same as / unless you define it otherwise in your problem statement.

If you intend the ÷ symbol to be used to indicate everything to its left is divided by everything to its right, it is appropriate to use parentheses for that grouping, as in ...

  (-----×1/4)÷(6×3/9) = (-----×1/4)÷2 = -----×1/8

_____

Here, we're going to evaluate what you have written according to the usual rules as described above.

  (-----×1/4)÷6×3/9 = -----×1/24×3/9 = -----×(3/24)/9

  = -----×1/8/9

  = -----×1/72

_____

<em>Comment on the arithmetic</em>

Fractions are multiplied and divided in the usual way:

  a/b×c = (a×c)/b

  a/b/c = (a/b) × (1/c) = a/(b×c)

___

<em>Comment on fractions and parentheses</em>

Please note that parentheses are required on any numerator or denominator that consists of anything other than a single number or variable. (The exception is the case where the numerator is a product, because a·b/c = (a·b)/c with or without the parentheses.)

6 0
3 years ago
Expand to write an equivalent expression: 4(-8x+6y)
Naddika [18.5K]

Answer:

-32x + 24y

Step-by-step explanation:

4(-8x + 6y) ⇒ -32x + 24y

4 0
3 years ago
Read 2 more answers
Pls help pls, i need this pls help
malfutka [58]

Answer:

Step-by-step explanation: a real one for the points

3 0
3 years ago
Find a normal subgroup of v which is not normal in a4.
Tpy6a [65]

he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).

Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.

6 0
3 years ago
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