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mario62 [17]
2 years ago
7

could someone please help me with this i suck at math and please try to explain to me how exactly i could solve it on my own lik

e the steps to solving it, thanks ill try to mark brainliest

Mathematics
2 answers:
anastassius [24]2 years ago
6 0

Answer:

18

Step-by-step explanation:

Just multiply them. 6 x 3 would be the formula in this situation. The other formula would be bh or bxh.

snow_tiger [21]2 years ago
5 0

Answer:

72

Step-by-step explanation:

6 times 4 equals 24, 24 times 3 equals 72

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2x+7=27 and 3x+1=28 does 2x+7= 3x+1
Savatey [412]
Hey there!

2x + 7 = 27
2x = 20
x = 10

3x + 1 = 28
3x = 27
x = 9

The values for both of these equations are 9 and 10; therefore, the answers are not equivalent.

I hope this helps!
5 0
3 years ago
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Which of the following is not an undefined term?
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Which of what following? Is it suppose to be multiple choice?
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3 years ago
You spin a spinner that has 15 equal-sized sections numbered 1 to 15. Find the theoretical probability of: P(odd number)
Basile [38]

Answer: The correct answer is

Step-by-step explanation:

8 0
3 years ago
What is the equation in slope-intercept form of the line that passes through the points (-4, 2) and (12, 6)? ​
BartSMP [9]

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Step-by-step explanation:

8 0
2 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
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