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3 years ago

3x+7=5x-21

2 answers:

7 0

Just get only one of the placeholder on one side by itself
and do the same thing to both sides so it stays equal
3x+7=5x-21
add 21 to both sides
3x+28=5x
subtract 3x from obht sides
28=2x
sivide both sides by 2
14=x

kompoz [17]3 years ago

3 0

3x + 7=5x-21
28=2x. Add 21 to both sides and subtract 3x on both sides
X=14 divide both sides by 2

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Directions:Use the product rule to simplify the following monomials.

sattari [20]

Answer:

19. 5x²y⁷

20. a³b²c⁷

21. 4a³b⁴

Step-by-step explanation:

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3 years ago

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3. Elizabeth is designing a ramp and a platform made of wood. Her sketch of the design

Nesterboy [21]

17x15=255ft

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3 years ago

A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. His

morpeh [17]

Answer:

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

$P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38$

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So $P(B) = 0.20$

P(A/B) is the probability that the person who made a day visit made a purchase. So $P(A/B) = 0.4$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053$

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So $P(B) = 0.50$

P(A/B) is the probability that the person who made a one night visit made a purchase. So $P(A/B) = 0.3$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474$

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So $P(B) = 0.30$

P(A/B) is the probability that the person who made a two night visit made a purchase. So $P(A/B) = 0.5$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474$

There is a 39.474% probability that this person made a two night visit.

3 0

4 years ago

1/2 of 12 = 1/4 of ?<br><br> 1/3 of 90 = 2/3 of?

ozzi

Answer: 1/2 of 12 = 1/4 of 24 and 1/3 of 90 = 2/3 of 45

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the y-intercept of the trend line above

photoshop1234 [79]

The y-intercept is about 2,150 since the line start at a little above 2,100.

7 0

3 years ago