Answer:
Eq: (x+a/2)²+(y+1)²=(a²-8)/4
Center: O(-a/2, -1)
Radius: r=0.5×sqrt(a²-8)
Mandatory: a>2×sqrt(2)
Step-by-step explanation:
The circle with center in O(xo,yo) and radius r has the equation:
(x-xo)²+(y-yo)²=r²
We have:
x²+y²+ax+2y+3=0
But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4
And
y²+2y+3=y²+2y+1+2=(y+1)²+2
Replacing, we get:
(x+a/2)²-a²/4+(y+1)²+2=0
(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4
By visual inspection we note that:
- center of circle: O(-a/2, -1)
- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)
Answer:
Factor −
28 out of −
56
z
+
28
.
answer = −
28
(
2
z − 1
)
Step-by-step explanation:
Hope this helps! Have a great day!
Answer:
I don't understand your question!!!
Answer:
(-1,0)
Step-by-step explanation:
3(-1)+3(0)=-3
-3+0=-3
-3=-3
-2(-1)+(0)=2
2+0=2
2=2
(a) Without solving the equation we can't determine whether its true or false.
(b) If x = 3
4x + 1 = 2x + 5
4(3) + 1 = 2(3) + 5
12 + 1 = 15 + 5
13 = 20
No, if x = 3, the equation will not be true.
(c) 4x + 1 = 2x + 5
4x - 2x = 5 - 1
2x = 4
x = 4/2
x = 2
This shows that x = 2 makes the equation true.
