A=-a (Constant)
vf=-at+v
r=-(1/2)at^2+vt+ro
d=r-ro definition
d=-(1/2)at^2+vt
rewriting
d=vt -(1/2)at^2
Answer:
Equation: ![30=2(x-2)+2(2x+3)](https://tex.z-dn.net/?f=30%3D2%28x-2%29%2B2%282x%2B3%29)
Step-by-step explanation:
By definition, the perimeter of a figure can be calculated by adding the lenghts of its sides.
Knowing this, you can write the following equation:
<em> [Equation 1]</em>
According to the data given in the exercise, the perimeter in feet of the fighter is:
![P=30](https://tex.z-dn.net/?f=P%3D30)
Therefore, you can substitute this values into<em> [Equation 1]:</em>
![30=2(x-2)+2(2x+3)](https://tex.z-dn.net/?f=30%3D2%28x-2%29%2B2%282x%2B3%29)
Finally, you must solve for "x" in order to find its value. This is:
![30=6x+2\\\\30-2=6x\\\\\frac{28}{6}=x\\\\x=\frac{14}{3}](https://tex.z-dn.net/?f=30%3D6x%2B2%5C%5C%5C%5C30-2%3D6x%5C%5C%5C%5C%5Cfrac%7B28%7D%7B6%7D%3Dx%5C%5C%5C%5Cx%3D%5Cfrac%7B14%7D%7B3%7D)
Not really, If you use the Pythagorean theorem on all problems related to distance.. You won't always be able to solve it. It depends on the numbers.
So, false.
Answer:
or (depends on what your curriculum requires)
Step-by-step explanation:
This question is asking for how many shares this person can buy when they have $2000 and each share costs $237.68
So how many 237.68s go into 2000? Well 2000 divided by 237.68 is roughly 8.14. However, you can not buy .14 of a share, so you round down to 8 full shares.
Now its time to write the inequality. Lets assign "x" as the amount of shares the character can buy. We know that they can buy as much as 8 shares, but remember that they can actually buy less than that, so anything below 8 shares and 8 shares would be x
8, indicating that x, the number of shares, can be 8 and anything less than that.
If you want to be really accurate, you could also add that x
0, since you cant buy 0 amount of shares. So then your answer would be
, meaning that they can buy between 0 and 8 shares, including 0 and 8
Lmk if this helped, was incorrect, or if you wanted me to clarify anything :)