The point slope form or the equation of a line is :
y - y1 = m(x - x1)
First find the slope between the two coordinates:
m = y2-y1/x2-x1
m = 0-4 / 2-(-6)
m = -4 / 8
m = - 1/2
Now create the point slope form / equation of a line:
y - 4 = - 1/2(x - (-6))
y - 4 = - 1/2(x + 6)
OR you can have
y - 0 = - 1/2(x - 2)
Answer:
48
To start you will find the area as if it was a rectangle. To do that you have to do 8x12. 8x12 = 96, but to find the area of a triangle you take the area of the rectangle and divide it by 2. 96 divided by 2 is equal to 48.
There are other methods of solving this but I think this is the easiest way!
A LmN > ; mqp by sas is the right answer
So you have to first put put the equation in slope-intercept form.
-3x+4y=4
+3x +3x
_______________
4y=4+3x
then you divide 4 by 4 and then divide 3x by 4 and you should get y=1+3/4x
then you plug in x and only x so that you can find y and then do the same once you find y
y=1+ (4)3/4
y= 1+3
y=4
then plug in y and solve for x
4= 1+ 3/4x
subtract 1 from both sides
3=3/4x
divide both sides by 3/4
and x=4
so then you find b and put it all in a equation.
<span> 1.04 x 10^2 in standard form = 104
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