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polet [3.4K]
3 years ago
10

Smith family had dinner at the restaurant. The cost of their meals was $45. They wanted to leave the waiter a 10% tip. They had

a $50 bill.
How much change would they receive after paying for the food and leaving the tip?
Mathematics
1 answer:
Digiron [165]3 years ago
6 0

Answer: 0.50

Step-by-step explanation: the tip was 4.50 (10% of 45) and so minus 50 and then minus 40 (50-45-4.50=0.50)

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Sorry for the quality but please help?!?!
gogolik [260]

Answer:

3/4

Step-by-step explanation:

28 total but 12 are boys so girls = 28 - 12 = 16

Ratio of boys to girls

= 12/16

= 3/4

6 0
2 years ago
7n + 6(n+4) -15 <br><br> how do i solve this with a step by step example
GrogVix [38]

Answer:

  13n +9

Step-by-step explanation:

There is nothing to solve. We can simplify the expression by eliminating parentheses and combining like terms.

  7n +6(n +4) -15 . . . . . . given

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8 0
2 years ago
What is 113.097335529 in terms of pi
V125BC [204]
36\pi
You would take 113.087335529 and divide by pi
6 0
3 years ago
Graph this solution x &lt; 4
morpeh [17]

Answer:

see below

Step-by-step explanation:

x < 4

x is less than 4

Since it is less than, there is an open circle at 4

less than means the line goes to the left

5 0
2 years ago
The American Veterinary Association claims that the annual cost of medical care for dogs averages $100 with a standard deviation
Taya2010 [7]

Answer:

The probability that the cost for someone's dog is higher than for the cat is 33.2%.

Step-by-step explanation:

With the data given, we know that the difference in cost of medical care of dogs and cats have a normal distribution with μ=-20 and σ=46.

To know the probability of the cost for the dog is higher than the cat, we have to calculate the probability of P(d>0).

Then we have to calculate z, and look up in a standarized normal distribution table.

Calculate z:

z=\frac{X-\mu}{\sigma}=\frac{0-(-20)}{46}=\frac{20}{46}=   0.4348

The probability of the difference being higher than 0, we have:

P(d>0)=P(z>0.4348)=0.33185

We can say that the probability that the cost for someone's dog is higher than for the cat is 33.2%.

8 0
2 years ago
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