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Annette [7]
3 years ago
7

- The two rectangles shown have equal areas. Find the value of x.

Mathematics
1 answer:
Anna [14]3 years ago
4 0
X= 36 I think

Hope this helps
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Which graph represents the solution to the system of inequalities?<br> x + y ≤ 4<br><br> y – x ≥ 1
frosja888 [35]

Given inequalities are

x+y\le4 and

y-x\ge1

Now we will graph both inequalities to get the common region which represents solution.

<u>Work for x+y\le4 </u>

first we graph the line x+y=4 then shade the graph for inequality symbol \le

we can plug any random number for x and find y-value to get points

lets plug x=0 then we get:

x+y=4

0+y=4

y=4

so the point is (0,4)

Similarly we can find more point like (4,0).

Now graph both points and join both points by straight line.

Now we find direction of shading.

pick any test point which is not on that line x+y=4 say (0,0)

and plug it into orinal inequality x+y\le4

0+0\le4

0\le4

which is true.

True means shade in direction of test point. Otherwise we shade in opposite direction.

We will repeat same process for other inequality to graph that.

Hence final graph for the answer will be as shown in attached image.

Triangular region ABC is final answer.

5 0
3 years ago
Solve for x, y, and z. <br> y=1/2z<br> x+2y+5z=2<br> 3x+6y-3z=9
Contact [7]
Rearrange the equation,

0x + y - ½z = 0 ==> Equation 1
x + 2y + 5z = 2 ==> Equation 2
3x + 6y - 3z = 9 ==> Equation 3

Put the 3 equation in matrix form,

0\ \ \ \ \ 1\ \ -{\frac{1}{2} }\ \ \ \ \ \ \ \ 0 \\ 1\ \ \ \ \ 2\ \ \ \ \ \ \ 5\ \ =\ 2 \\ 3\ \ \ \ \ 6\ \ -3\ \ \ \ \ \ \ \ \ 9

Find the determinant, D, of the matrix,

0\ \ \ \ \ 1\ \ -{\frac{1}{2} } \\ 1\ \ \ \ \ 2\ \ \ \ \ \ \ 5\ = \ D \\ 3\ \ \ \ \ 6\ \ -3

By Sarrus' rule,
D = [(0 × 2 × -3) + (1 × 5 × 3) + (-½ × 1 × 6)] - [(-½ × 2 × 3) + (5 × 6 × 0) + (-3 × 1 × 1)]
D = [0 + 15 + (-3)] - [(-3) + 0 + (-3)]
D = 12 + 6
D = 18

By cramer's rule,

x = Determinant of x ÷ D
Let determinant of x = Dx,

0\ \ \ \ \ 1\ \ -{\frac{1}{2} } \\ 2\ \ \ \ \ 2\ \ \ \ \ \ \ 5\ = \ Dx \\ 9\ \ \ \ \ 6\ \ -3
To get this determinant, substitude 0, 2 and 9 with the unknown you're finding, in this case, x.

By Sarrus' rule,
Dx = [(0 × 2 × -3) + (1 × 5 × 9) + (-½ × 2 × 6)] - [(-½ × 2 × 9) + (0 × 5 × 6) + (-3 × 1 × 2)]
Dx = [0 + 45 + (-6)] - [-9 + 0 + (-6)]
Dx = 39 + 15
Dx = 54

x = Dx ÷ D
x = 54 ÷ 18
x = 3

By cramer's rule,

y = Determinant of y ÷ D
Let determinant of y = Dy

0\ \ \ \ \ 0\ \ -{\frac{1}{2} } \\ 1\ \ \ \ \ 2\ \ \ \ \ \ \ 5\ = \ Dy \\ 3\ \ \ \ \ 9\ \ -3

By Sarrus' rule,
Dy = [(0 × 2 × -3) + (0 × 5 × 3) + (-½ × 1 × 9)] - [(-½ × 2 × 3) + (5 × 9 × 0) + (-3 × 0 × 1)
Dy = [0 + 0 - 4½] - [-3 + 0 + 0]
Dy = -4½ + 3
Dy = -1½

y = Dy ÷ D
y = -1½ ÷ 18
y ≈ 0.0833 (3 significant figure)

Solving z using equation rule,
y = ½z
0.0833 = ½z
z = 0.0833 ÷ ½
z ≈ 0.167 (3 significant figure)

∴ x = 3, y = 0.0833 and z = 0.167.
7 0
3 years ago
HELP ASAP WILL MARK BRAINLEST!!!!!
kondaur [170]

Answer:

THE ANSWER IS 45 thank me later!!!

Step-by-step explanation:

5 0
3 years ago
What is 31/50 as a percentage
natita [175]
x\ as\ a\ prcentage:\\\\x=x\cdot100\%\\--------------------------\\\\\frac{31}{50}=\frac{31}{50}\cdot100\%=(31\cdot2)\%=\boxed{62\%}
5 0
3 years ago
Read 2 more answers
Solve the following equation for x.<br> 3(1+5) = 1 + 19<br> The solution is x =
atroni [7]

Answer :

3 (1 + 5) = 1 + 19

3(6) = 20

18 = 20

x = 20-18

x = 2 is the answer

Hope it helped

4 0
2 years ago
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