4. Find the value of a, for which point p (a/3,2) is the midpoint of the line segment
1 answer:
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Answer: 58 ft × 58 ft
Step-by-step explanation:
Let the length of the region = x feet
And, the width of the region = y feet
Since, the perimeter of the region = 234 feet ( Given )
⇒
⇒
⇒
Again the area of the region, A = xy
⇒
⇒
By differentiating the above equation with respect to x,
⇒
For maxima or minima,
Again differentiating equation A'(x) with respect to x,
We get, A''(x) = -2
Hence, For x = 58.5 A''(x) = negative
⇒ For x = 58.5 feet the area A(x) is maximum,
⇒ The length of the region having maximum area = x = 58.5 feet
And, the width of the region having maximum area = y = 117-x= 117 - 58.5=58.5 feet,
⇒ The dimension of the region having the maximum area = 58.5 ft × 58.5 ft