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makkiz [27]
3 years ago
11

Show that cos 30 degree + sin 60 degree / 1+ sin 30 degree + cos 60 degree is equal to cos 30 degree​

Mathematics
1 answer:
Soloha48 [4]3 years ago
5 0

Answer:

cos 30

Step-by-step explanation:

cos 30 + sin 60 / 1+ sin 30 + cos 60

= root3 / 2 + root3/2 / 1 + 1/2 + 1/2

= root 6/2 by 4/2

= root 6/4

= root 3/2

= cos 30

You might be interested in
The probability that a randomly selected box of a certain type of cereal has a particular prize is 0.20.
MatroZZZ [7]

Answer:

a) the probability is 0.0734 (7.34%)

b) the probability is 0.7382 (73.82%)

c) 10 boxes

Step-by-step explanation:

Since each box is independent of the others and defining the random variable X= number of boxes of cereal purchased without prices until having 2 prices , then X has a negative binomial distribution . Thus

P(X=k)= C(k+r-1,k)*p^k *(1-p)^r

where

p= probability to not obtain a price when a box is purchased = 1- 0.2 = 0.8

C ( ) = combinations

k = number of boxes without prices

r= number of boxes with prices=2

P(X=k) = probability of purchasing k boxes without prices until obtaining r boxes with prices

a) for k= 8 - r = 6

P(X=6)= C(7,6)*0.8^6*0.2^2 = 7*0.8^6*0.2^2 = 0.0734 (7.34%)

b) for k≥9-2=7

P(X≥7) = 1- P(X<7)= 1- Fn(X=7)

where Fn(X) is the cumulative negative binomial distribution. We can calculate it through its relationship with the cumulative binomial distribution Fb(X) that is easily found in tables :

Fn(k=7,r=2,p=0.8) = Fb(k=7,n=k+r=9,p=0.8) = 0.2618

thus

P(X≥7) = 1- P(X<7)= 1- Fn(X=7) = 1-  0.2618 = 0.7382 (73.82%)

c) the expected value E(X) for a negative binomial distribution is

E(X)= p*r/(1-p) = 0.8*2/0.2 = 8 boxes that do not contain prices

thus

n=k+r = 8 + 2 = 10 boxes

6 0
3 years ago
L<br> E<br> N<br> 4<br> 8<br> 1<br> O<br> k<br> M<br> What is the value of k?<br> k=
s2008m [1.1K]

Answer: 2

Step-by-step explanation:

By the geometric mean theorem,

\sqrt{8k}=4\\\\8k=16\\\\k=\boxed{2}

6 0
2 years ago
What is the value of the numerical expression 5/8-5/12(3-1/4)+2/3
vlabodo [156]
Make bottom numbers same
find least common multipules of 8,12,4 and 3
8=2 times  2 times 2
12=2 times 2 times 3
4=2 times 2
3=3
lcm=2 times 2 times 2 times 3=24

5/8 times 3/3=15/24
5/12 times 2/2=10/24
3/1 times 24/24=72/24
1/4 times 6/6=6/24
2/3 times 8/8=16/24
we now have
15/24-10/24(72/24-6/24)+16/24
pemdas
simplify parenthasees first
72/24-6/24=66/24

now we have
15/24-10/24(66/24)+16/24
multiply
15/24-660/576+16/24
make same bottom number
15/24 times 24/24=360/576
16/24 times 24/24=384/576
360/576-660/576+384/576
84/576
7/48

answer is 7/48
3 0
3 years ago
WORTH 50 POINTS!!
cluponka [151]

Answers:  Choice A and Choice E

0.82B  and  B-0.18B

========================================================

Explanation:

B is the cost of the game (some unknown amount). Subtract off 0.18B to indicate a 18% reduction in the price. That's how we get choice E.

Simplifying choice E leads us to choice A. Notice that 1 - 0.18 = 0.82; which represents 100% - 18% = 82%. After the discount, Bo is paying 82% of the original price.

Side note: Choice B indicates an 18% increase. Choices C and D don't represent percentage decreases (rather they're decreasing by a fixed amount regardless of what B is).

4 0
2 years ago
The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?
Paul [167]

Answer:

The standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

Let (x_{1},y_{1}) and (x_{2},y_{2}) be the given points (6,2) and (-2,5) respectively.

M=(\frac{6-2}{2},\frac{2+5}{2})

M=(\frac{4}{2},\frac{7}{2})

M=(2,\frac{7}{2})

Therefore the center (h,k) is (2,\frac{7}{2})

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

=\sqrt{(-2-6)^2+(5-2)^2}

=\sqrt{(-8)^2+(3)^2}

=\sqrt{64+9}

=\sqrt{73}

Therefore the radius is \sqrt{73}

i.e., r=\sqrt{73}

Therefore the standard form of the circle is

(x-h)^2+(y-k)^2=r^2

Now substituting the center  and radiuswe get

(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2

(x-2)^2+(y-\frac{7}{2})^2=73

Therefore the standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

5 0
3 years ago
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