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USPshnik [31]
3 years ago
8

A bike brought for £100 was sold for 20% les. What was the selling price​

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:

it should be 80

Step-by-step explanation:

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The radius of a circle with an area of 8 cm2 will be enlarged by a scale factor of 4.
GarryVolchara [31]

Answer:

I believe the answer is 32 because you multiply it in enlarging.

8 0
3 years ago
How would you write this number in numeric form?
liberstina [14]
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0.034
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Find the 23rd term of the arithmetic sequence 17, 19, 21, 23, ...
olga55 [171]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Two sides of a right triangle measure 222 units and 444 units. What is the area of the square that shares a side with the third
jasenka [17]

Answer:

the area of the square = x² = 147,852 ft²

Step-by-step explanation:

Given;

two sides of a right triangle, = 222 units and 444 units

let the third side of the right triangle that shares a side with a square = x

the third side is obtained by applying Pythagoras theorem, and assuming the third side to be either adjacent or opposite side.

x² = 444² - 222²

x² = 147,852

x = √147,852

x = 384.52 ft

Therefore, the area of the square = x² = 147,852 ft²

4 0
3 years ago
Read 2 more answers
Noise levels at 5 volcanoes were measured in decibels yielding the following data: 127,174,157,120,161 Construct the 98% confide
slavikrds [6]

Answer:

The critical value used is T = 3.747.

The 98% confidence interval for the mean noise level at such locations is (108.944, 186.656).

Step-by-step explanation:

Before building the confidence interval, we need to find the sample mean and the sample standard deviation.

Sample mean:

\overline{x} = \frac{127+174+157+120+161}{5} = 147.8

Sample standard deviation:

s = \sqrt{\frac{(127-147.8)^2+(174-147.8)^2+(157-147.8)^2+(120-147.8)^2+(161-147.8)^2}{4}} = 23.188

Confidence interval:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 5 - 1 = 4

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 4 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 3.747, which is the critical value used.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 3.747\frac{23.188}{\sqrt{5}} = 38.856

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 147.8 - 38.856 = 108.944  

The upper end of the interval is the sample mean added to M. So it is 147.8 + 38.856 = 186.656.

The 98% confidence interval for the mean noise level at such locations is (108.944, 186.656).

8 0
3 years ago
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