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ICE Princess25 [194]
3 years ago
11

I Really need Help IF you know how to do this please help!

Mathematics
1 answer:
UkoKoshka [18]3 years ago
4 0

okay so basically we see two rectangles right, so we can subtract the small from the big to leave the shaded region behind: so we take the area of the big rectangle first, (x+5)*4 and then we subtract the small area which is 2*2 so that we get an equation like this: (x+5)*4 - 4 --> 4x+20-4 --> 4x+16

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Only number 8 plsssss bet no one can get this
Nesterboy [21]

Answer:

52 sq un

Step-by-step explanation:

8 0
3 years ago
A skyrocket is launched from a 30–foot-high platform, with initial speed 300 ft/s. If the polynomial −16t2 + 300t + 30 gives the
Stella [2.4K]

Answer:

566 ft

Step-by-step explanation:

Given the polynomial equation

-16t² + 300t + 30 = 0

We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have

-16 * 2² + 300 * 2 + 30

-16 * 4 + 600 + 30

-64 + 630 = 566 ft

Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft

8 0
3 years ago
Does the addition problem show a way to add 27 + 38?
Dmitry [639]

Answer:

a. yes

b. no

c. yes

d. yes

Step-by-step explanation:

For a, 27 + 38 can be broken apart. 27 is broken up by adding smaller numbers (20 + 7 = 27) and the same is done with 38 (30 + 8 = 38), so A and C shows a way to add 27 and 38. In C, the numbers are just put into a different order. B is not a way to add 27 and 38, because the sum is different.

27 + 38 = 65, however 20 + 70 + 38 = 128. The addition problem for D is a way to solve for 27 + 38, because it is broken up differently than A and C. They instead added the 20 and 30 together first, then split up 15 (from 8+7) into 10 and 5. So D is a way to solve, because it gets the same answer as 27 and 38 :D

8 0
4 years ago
Which step is the same when constructing an inscribed regular hexagon and an inscribed equilateral triangle?.
Naddik [55]

Step is the same when constructing an inscribed regular hexagon and an inscribed equilateral triangle is shown below:

<h3 /><h3>What is construction?</h3>

Geometric construction is the process of drawing a geometrical figure using two geometrical instruments, a compass, and a ruler.

Construction of an inscribed regular hexagon

1) Set compass width to the radius of the circle

2) Make an arc on the circle with the set radius.

3) From the previous arc draw another arc with the same radius.

4) Continue this process for the other vertex.

5) Connect all the vertices.

Construction of an inscribed equilateral triangle

1) Set compass width to the radius of the circle

2) Make an arc on the circle with the set radius.

3)From the previous arc draw another arc with the same radius.

4)Continue this process for the other vertex.

5) Connect the every other vertices point by drawing  a line between every other adjacent vertex point to form an inscribed equilateral triangle.

Learn more about construction here:

brainly.com/question/791518

#SPJ1

7 0
2 years ago
Find the shorter base of a trapezoid if the trapezoid's area is 52, its altitude is 8, and its longer basis 10.
DiKsa [7]

Answer:

The shorter base is 3

Step-by-step explanation:

a =  \frac{(b1 + b2)}{2}  \times h

52 =  \frac{(10 + b2)}{2}  \times 8

b2 = 3

8 0
3 years ago
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