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ICE Princess25 [194]
3 years ago
12

Help me. this IS NOTa quiz

Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer:

unbalanced

Step-by-step explanation:

The force to the right is 25+35 = 60

The force to the left is 15

This is unbalanced

60 does not equal 15

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10. Only 40% of the Raptor Club's members returned the club's hawk survey. The club has 65 members. How many took part in the su
matrenka [14]
40% of 65
0.40(65) = 26 returned the survey. (assuming that everybody who took the survey returned it.)
3 0
3 years ago
jacob used 1/7 of a liter to fill 1/9 of the fush aquarium. how many liters if water are needed to fill the aquariam? please lea
Sveta_85 [38]

Answer:

1.2 liters

Step-by-step explanation:

7/7 of a liter is one liter. and you still are only at 7. you need to get to 9 you and 2 1/7 liters and that becomes 9/7 liters which = 1.2

7 0
3 years ago
If my assignment is worth 14% of my quiz weight which is 27% of my total weight what is the weight of that assignment
Nimfa-mama [501]

Answer:

3.785%

Step-by-step explanation:

Assignment is 14% of the quiz

=> Assignment = 14% of the quiz

Quiz is 27% of the total weightage

=> 14% of 27%

<u>Find 14% of 27% </u>

14% of 27%

= 0.14 x 27 = 3.785%

The assignment is 3.785% of the total weightage.

6 0
3 years ago
Answer to this question?
Readme [11.4K]
A midsegment is given by the formula:
\frac{x1+x2}{2} , \frac{y1+y2}{2}

Where x1, x2, y1, and y2 correspond to their respective coordinates. We can do the equation:

\frac{-3+5}{2} , \frac{-1+3}{2}
This gets us a midpoint coordinate of <span>(1,1)

</span>As for distance, it will be found by doing:
\sqrt{(x2-x1)^2+(y2-y1)^2}
We can do the following:

\sqrt{(5-(-3))^2+(3-(-1))^2}
\sqrt{(8)^2+(4)^2}
\sqrt{64+16}
This simplifies to 4 \sqrt{5}

:)
5 0
3 years ago
Read 2 more answers
On which number line are −4 and its opposite shown?
Natasha2012 [34]

Answer:

it is D because it is asking for the opposite of -4 so it would be the tick mark on -4 and 4

Step-by-step explanation:

5 0
2 years ago
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