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topjm [15]
3 years ago
13

Jason and his children went into a grocery store and will buy bananas and mangos. Each banana costs $0.90 and each mango costs $

2. Jason has a total of $25 to spend on bananas and mangos. Write an inequality that would represent the possible values for the number of bananas purchased, bb, and the number of mangos purchased, m.m.
Mathematics
1 answer:
Andrej [43]3 years ago
8 0

Answer:

25 ≥ 0.90b + 2m

Step-by-step explanation:

Given:

Cost of each banana = $0.90

Cost of each mango = $2

Total amount = $25

Find:

Inequality

Computation:

Assume;

Number of banana = b

Number of mango = m

Total amount ≥ Cost of total banana + Cost of total mango

25 ≥ 0.90b + 2m

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alexgriva [62]
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Round 253.5198 to the nearest thousandth
kipiarov [429]

Answer:

253.520

Step-by-step explanation:

Let us see what is the thousandths place...

It is the third digit to the right.

253.5198 rounded is about

253.520.

I can tell because you take the thousandths place, look at the one to the right of it, then if it is greater than 5, you make the thousandths place greater. Since it's a 9, you move the extra 10 thousandths to the next thing- the hundredths. and you get 253.520.

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3 years ago
Read 2 more answers
Select the following series as finite or infinite.
amm1812

Answer:

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3 years ago
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1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.
iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is 53.13\°

Part 2) The surface area of the pyramid is 288\ cm^{2}

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

sin(x)=\frac{16}{20}

x=arcsin(\frac{16}{20})=53.13\°

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

SA=b^{2}+4[\frac{1}{2}(b)(h)]

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

h=b/2 -------> by an 45° angle

so

b=2h

sin(45\°)=\frac{h}{6\sqrt{2}}

h=6\sqrt{2}(sin(45\°))=6\ cm

Find the value of b

b=2(6)=12\ cm

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3 years ago
Please help i’ll mark
vlabodo [156]

either contradiction or not a linear equation

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2 years ago
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