All categories

3 years ago

What is the slope of the line passing through (2,2) and (10,6)

Mathematics

1 answer:

frutty [35]3 years ago

7 0

Answer: y=2x-2

Step-by-step explanation:

You might be interested in

A salesperson's weekly paycheck is 10% more than a second salesperson's paycheck. The two paychecks total $1525. Find the amount

Kaylis [27]

1525 ➗ 2 = 762.5
762.50 x 10% is 76.25
762.50 - 76.25 = 686.25
one paycheck is 762.50
the other is 686.25

I hope this helps.

6 0

3 years ago

HELP ASAP, PLS DONT JOKE

Alik [6]

Answer:

ejejjejejejeje its ocean answer plzzz

Step-by-step explanation:

8 0

3 years ago

The two rectangles below are similar. What is the measurement of the missing side of the rectangle?

r-ruslan [8.4K]

B

You would divide 45 mm/15mm to get 3. Multiply 3 by 27 to get 81 mm.

5 0

3 years ago

Having trouble with this

GaryK [48]

Jayden ran 1/5 of his total distance in 1 minute. His total distance is 6/5 of a kilometer. He ran 6/25 of a kilometer in 1 minute or 3/5 of a lap.

7 0

3 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

1 year ago