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maxonik [38]
2 years ago
9

The radius of a circle is 5 inches What is the circumference of the circle?​

Mathematics
1 answer:
givi [52]2 years ago
8 0

Answer: 31.41592654 inches

Step-by-step explanation:

C = pi (d)

C = pi (10)

C = 31.41592654 inches

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Change 1/2 as a fraction
dimaraw [331]

Answer:

0.50 ,1/2 as a fraction 1/2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey
Lubov Fominskaja [6]

Answer:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

Step-by-step explanation:

For this case we have the following distribution given:

X        0         1       2       3       4         5        6

P(X)  0.3   0.25   0.2   0.12   0.07   0.04   0.02

For this case we need to find first the expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And replacing we got:

E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61

Now we can find the second moment given by:

E(X^2) =\sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97

And the variance would be given by:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

 

8 0
3 years ago
Find equations of the line that is parallel to the z-axis and passes through the midpoint between the two points (0, −4, 9) and
Lorico [155]

Answer: x = -4, y = 0.5, z = 5 +t

Hi!

The line L whose direction is parallel to vector V a passes through point A

is parametrized

P_L = Vt + A

Where t, is a real number, and P_L is a any point on line L.

In this case the direction is that of the z-axis , so V = (0, 0, 1)

A is the midpoint between points B = (0, -4, 9) and C=(-8, 5, 1)

The midpoint is A = (B + C)/2 = (-4, 0.5, 5)

Then the line is:

P_L = (0,0,1) t + (-4, 0.5, 5)

The equations for each coordinate are:

x = -4\\y = 0.5\\z = 5 + t

7 0
3 years ago
Which of the following points could be added to the graph f(x)=-|x+3| to keep the graph a function?
sasho [114]

None of the points could be added to the graph f(x)=-|x+3| to keep the graph a function

<h3>How to determine the point?</h3>

The equation of the function is given as:

f(x) = - |x + 3|

The points are given as:

(0, 3) and (-3, -6)

When x = 0, we have:

f(0) = - |0 + 3|

f(0) = -3 --- different y value from (0, 3)

When x = -3, we have:

f(-3) = - |-3 + 3|

f(-3) = 0 --- different y value from (-3, -6)

This means that the x values point to different y values (this does not represent a function)

Hence, none of the points could be added to the graph f(x)=-|x+3| to keep the graph a function

Read more about functions and relations at:

brainly.com/question/2328150

#SPJ1

6 0
2 years ago
Which function described as the arithmetic sequence below 1,-2,-5,-8,-11
motikmotik

Answer:

-3 it subtracts if you take 1and go back 3 times you get -3 same. for negative -5 back -3 is -8

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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