Answer:
45
Step-by-step explanation:
Assuming this is a trapezoid,
.95 in decimal form and 95/100 as a fraction or 19/20
To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by
1/12.5 = 0.08, or 8%
We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
Answer:b. 0.22
Step-by-step explanation:
Since the lengths of adult walleye fishes are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = lengths of walleye fishes.
µ = mean length
σ = standard deviation
From the information given,
µ = 44 cm
σ = 4 cm
We want to find the probability or fraction of fishes that are greater than 41 cm in length. It is expressed as
P(x > 41) = 1 - P(x ≤ 41)
For x = 41,
z = (41 - 44)/4 = - 0.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.22
Answer:
C
Step-by-step explanation:
The width is 5 yds longer so we can mark out b and d if you multiply 19 and 24 is 456 so you are left with C
