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3 years ago

Solve for x. 3x + 2 2x + 6 x = [?]

Mathematics

1 answer:

AVprozaik [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Im assuming you mean the first and second equation equal each other:

3x+2=2x+6

x=4

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Anwser true or false

m_a_m_a [10]

False because doing the math doesn’t match

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3 years ago

Read 2 more answers

3x + ky = 8

sattari [20]

Answer:

(a): x is 3 and ky is -1

(b): k is -2

Step-by-step explanation:

Let: 3x + ky = 8 be equation (a)

x - 2 ky = 5 be equation (b)

Then multiply equation (a) by 2:

→ 6x + 2ky = 16, let it be equation (c)

Then equation (c) + equation (b):

${ \sf{(6 + 1)x + (2 - 2)ky = (16 + 5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}$

Then ky :

${ \sf{2ky = 3 - 5}} \\ { \sf{ky = - 1}}$

${ \bf{y = \frac{1}{2} }} \\ { \sf{ky = - 1}} \\ { \sf{k = - 2}}$

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3 years ago

Express 5/21 as a decimal...please help !

Rudik [331]

5/21 = 5 ÷ 21 = 0.238

4 0

3 years ago

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Daniel is using logarithms to solve the equation 2^4x = 14. Which of the following equations would be equivalent to his original

ycow [4]

Remember
$log_a(b^c)=(c)log_a(b)$
so
$2^{4x}=14$ take the log of both sides
$log(2^{4x})=log(14)$ or
$4xlog(2)=log(14)$

B is the answer

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3 years ago

X + 4y = 23 -3x = 12y + 1 is it no solution?

bagirrra123 [75]

Answer: Yes

Step-by-step explanation:

First multiply the first equation by three to get 3x+12y=69

Then subtract 12y from both sides of the second equation

Then add the first system and the second like this:

$3x+12y=69\\-3x-12y=1\\--------\\0+0=70\\0=70$

Because 0≠70, the system has no solutions

5 0

3 years ago