<h3>
Answer: n = -11</h3>
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Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
Step-by-step explanation:
Use midpoint formula,
x = -6/2 = -3 , y=2/2 =1
(x,y)=(-3,1)
so , the coordinates of mid point of line segment is M (-3,1)


|x - 5| = 16
x - 5 = +/- 16
x - 5 = 16 or x - 5 = -16
<u> +5</u> <u>+5 </u> <u> +5 </u> <u>+5 </u>
x = 21 or x = -11
Answer: x = {21, -11}
A=6a^2
A=6(5.5)^2
A=181.5
Hopefully I answered correctly.