Question

Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data sets shown are true?
City A

A box-and-whisker plot. The whiskers have a range of 10 and the box has a range of 3.

City B

A box-and-whisker plot. The whiskers have a range of 18.5 and the box has a range of 9.5.
City A is likely to have a colder temperatures because the interquartile range is smaller than that of City B.
City A is likely to have temperatures that remain fairly constant year round because it has a compact interquartile range compared to that of City B.
City A is likely to have very hot days and extreme temperatures because the mean is larger than that of City B.
City B is likely to have more warm days than City A because the maximum value is greater.
City B is likely to have more extreme temperatures with colder days in winter and hotter days in summer

Answer 1

9514 1404 393
Answer:
Part A: 2 f2
Part B: draw a diagonal (AC, for example); 1 f12
Step-by-step explanation:
Part A:
The area of a parallelogram is given by the
formula
A=bh
where "b' is the length of the base, and 'h' is the
perpendicular distance between the bases.
Using the numbers shown on the diagram, the
area is
A = (3 ft)(2/3 ft) = 3-2/3 f12
A =2 ft2..... area of the parallelogram
Part B:
Typically, a polygon is partitioned into triangles
by drawing diagonals from one of the vertices. It
does not matter which one. (In a quadrilateral,
only one diagonal can be drawn from any given
vertex.) Here, the "base" of each triangle is the
same as the base of the parallelogram: 3 feet.
The "height" of each triangle is the same as the
height of the parallelogram: 2/3 ft.
The area of a triangle is given by the formula