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2 years ago

11

(50 POINTS)(WILL GIVE BRAINYEST)(STEP BY STEP ANSWER PLS) it would be very much appreciated if someone could help me on this pro

blem the question in in the screenshot, thanks in advance :D

1 answer:

Lilit [14]2 years ago

8 0

50% = $20
25% = $10
40+10 = $50
original price = $50

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4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

2 years ago

Anyone know this please???

Kazeer [188]

Answer: Choice A

The triangles are congruent because both the corresponding sides of the triangles and the corresponding angles of the triangles are congruent.

==============================================

Explanation:

Congruent triangles are identical copies of one another. This means the corresponding pieces must be the same.

It's like saying two houses are identical, so that means the all the various parts (eg: front door, windows, etc) must be identical. If let's say the two front doors were different, then the houses wouldn't be completely identical.

Going back to the triangles, we know that the sides are congruent by the tickmarks

side MN = side RS (single tickmark)
side NP = side ST (double tickmarks)
side MP = side RT (triple tickmarks)

That takes care of the first part of choice A.

And similarly, the angle markers tell us which angles are congruent

angle M = angle R (single arc)
angle N = angle S (90 degree angle marker)
angle P = angle T (double arc)

That concludes the second part of choice A.

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2 years ago

Solve −4(x + 10) − 6 = −3(x − 2).

Dmitriy789 [7]

Should be the right answer ☺️

4 0

3 years ago

Read 2 more answers

Please help ASAP :ppppp

Morgarella [4.7K]

Answer:

I think it's c

Step-by-step explanation:

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2 years ago

Anyone know the answer to this algebra problem?

ikadub [295]

Answer: $\bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}$

<u>Step-by-step explanation:</u>

$\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}$

$\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}$

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2 years ago