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slamgirl [31]
3 years ago
7

Suppose you physically simulate the random process of rolling a single die. ​(a) After 1010 rolls of the​ die, you observe a​ "o

ne" 44 times. What proportion of the rolls resulted in a​ "one"? ​(b) After 2020 rolls of the​ die, you observe a​ "one" 22 times. What proportion of the rolls resulted in a​ "one"?
Mathematics
1 answer:
forsale [732]3 years ago
8 0

Answer:

(a) 0.4 or 40%

(b) 0.1 or 10%

Step-by-step explanation:

(a) If you get 4 "ones" after 10 rolls of the die, the proportion of the rolls that resulted in "ones" is:

p=\frac{4}{10}\\ p=0.4

(b) If you get 2 "ones" after 20 rolls of the die, the proportion of the rolls that resulted in "ones" is:

p=\frac{2}{20}\\ p=0.1

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<h3>sin22° = 5/4</h3><h3>tan22° = 3/√55</h3>

As we know that , sinA = opposite/hypotenuse & tanA = opposite/adjacent

So here we can find sin22° , because they already given the sides opposite & hypotenuse . And we can't find tann22° because they given the value of opposite but not given the value of adjacent side of the angle 22°

Now finding the adjacent side using

Pythagoras theorem :-

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