The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <=
![4 \sqrt{7}](https://tex.z-dn.net/?f=4%20%5Csqrt%7B7%7D%20)
W <=
![\frac{4 \sqrt{7} }{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%20%5Csqrt%7B7%7D%20%7D%7B3%7D%20)
cm
Answer:
27x^3 - 54x^2 + 36x - 8
Step-by-step explanation:
(3x - 2)^3
= (3x - 2) (3x - 2) (3x - 2)
= 27x^3 - 54x^2 + 36x - 8
Hope this helps :)
Let me know if there are any mistakes!!
Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ =
L.H.S = sin θ cos θ
so, sin θ cos θ ≠ ![\frac{cos \ \theta}{sin \ \theta}](https://tex.z-dn.net/?f=%5Cfrac%7Bcos%20%5C%20%5Ctheta%7D%7Bsin%20%5C%20%5Ctheta%7D)
So, the equation is not a trigonometric identity.
=========================================================
<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
7/9% is not 7/9 of 1, it's 7/9 of 0.01.
So, it is 0.0078
Hope this helps!
Answer:
x=3
Step-by-step explanation:
You can solve by:
5x+7=-3x-31
adding 3x to each side:
8x+7=31
Subtract 7 from each side:
8x=24
Divide each side by 8:
x=3
That is your answer
Hope this helps!