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sweet [91]
3 years ago
15

​m = 3 and the line goes through the point (2,4)

Mathematics
2 answers:
kirill [66]3 years ago
5 0
Hi I’m just writing this so I can get some points sorry I can’t help
Troyanec [42]3 years ago
4 0

Answer:

then you will need to wait for thsi can get you to your area

Step-by-step explanation:

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What is the image of (-1,8) after translation right 1 units and up 2 units
Vladimir79 [104]

Answer:(0,10)

Step-by-step explanation: Im pretty sure because of subtracting 1 from the -1 in your x value and adding 2 to the 8 in you Y value

4 0
3 years ago
True or false? A convex shape curves outwards.
Margaret [11]
The answer is true. Hope this helps. Mark brainest

6 0
3 years ago
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the coordinates of a pentagon ABCDE are A(-5,4),B (1,4),C(1,-1), D(-2,-5) and E(-5,-1) what is the perimeter of the pentagon
kogti [31]
Perimeter is a continuous line forming the boundary of a closed geometrical figure. perimeter of a pentagon = AB+BC+CD+DE+EA (that is 5 sided figure) 
so my plan is easy but effective, calculate all those distances using those coordinates with the aid of distance formular. then you add those distances algebraically .
7 0
3 years ago
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Please help me out solve it and tell me how you got that answer so I can understand please!
NikAS [45]

The solution for s in the given equation is s = C-nD

The question seems to be incomplete

Here is the complete question:

Solve for s in this equation D= \frac{C-s}{n}   Depreciation.

To solve for s, that means we should make s the subject of the equation

From the given equation,

D= \frac{C-s}{n}

To solve for s, first multiply both sides by n to clear the fraction

We get

n\times D= n \times \frac{C-s}{n}

Then,

nD = C - s

Now, add s to both sides

nD + s= C - s+s

nD+s = C

Then, subtract nD from both sides

nD-nD+s = C-nD

∴ s = C-nD

Hence, the solution for s in the given equation is s = C-nD

Learn more here: brainly.com/question/21406377

6 0
2 years ago
Georgetown and Franklin are 9.7 in apart on a map that has a scale of 1.1 in : 15 mi. How far apart are the real cities?
lina2011 [118]
\bf \begin{array}{ccllll}
inches&miles\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1.1&15\\
9.7&x
\end{array}\implies \cfrac{1.1}{9.7}=\cfrac{15}{x}\impliedby \textit{solve for "x"}
5 0
3 years ago
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