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3 years ago

GEOMETRY. PLEASE INCLUDE CLEAR ANSWER AND EXPLANATION

Mathematics

1 answer:

Elodia [21]3 years ago

3 0

Remark

The 29o angle is made up of a line that looks horizontal and the hypotenuse.

The only way to solve this is to assume the horizontal line just mentioned and x are parallel. If that is so, the angle of the triangle on your right is 29o as well.

Step One

Set up the equation.

You are using a right angle triangle using the 29o angle on the lower right that we defined in the remark section.

Cos(29) = adjacent / hypotenuse.

Adjacent = x

Hypotenuse = 500

Cos(29) = 0.8746

0.8746 = x / 500 Multiply both sides by 500

x = 0.8746 * 500

x = 437.3

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What’s The Answer Of This? PLEASE HELP

gulaghasi [49]

Answer: 68 degrees

Step-by-step explanation:

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2 years ago

The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of

SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 20.8, \sigma = 4.5$

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 20.8}{4.5}$

$Z = 0.04$

$Z = 0.04$ has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{23 - 20.8}{4.5}$

$Z = 0.71$

$Z = 0.71$ has a pvalue of 0.7611

X = 18

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{18 - 20.8}{4.5}$

$Z = -0.62$

$Z = -0.62$ has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

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3 years ago

In a regular 52 deck of cards, what is the probability of picking a random spade, a 4 of any suit and then a random diamond with

meriva

$sample \: space = 52 \: cards \\ spades = 13 \: cards \\ number \: 4s = 4 \: cards \\ diamonds = 13 \: cards \\ note \: that = \\ there \: is \: replacement \\ order \: does \: matter$

$P( \gamma ) = \frac{13}{52} \times \frac{4}{52} \times \frac{13}{52} = \frac{1}{208}$

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2 years ago

A truck is carrying 8 cars weighting an average of 4500 pounds each. What is the total weight in tons of the cars on the truck?

umka2103 [35]

Answer:

the total weights in tons is 18

Step-by-step explanation:

The computation of the total weights in tons is shown below:

The weight of 8 cars would be

= 4,500 pounds × 8 cars

= 36,000 pounds

Now as we know that 1 ton = 2,000 pounds

So for 8 trucks it would be

= 36,000 pounds ÷ 2,000 pounds

= 18 tons

Hence, the total weights in tons is 18

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3 years ago

How many more unit tiles must be added to the function f(x)=x2−6x+1 in order to complete the square?

Valentin [98]

<h2>8 unit tiles should be added</h2>

Step-by-step explanation:

Function given is $f(x)=x^{2}-6x+1$ . We wish to add more unit tiles to the function so that it becomes a complete square.

Since the given function is of order 2, the side of the square will be order 1. Let us assume a general order 1 expression $ax+b$ to be the side of the square.

As the function forms the square after adding some $p$ unit tiles, $f(x)+p=(\text{Side of square})^{2}$

$x^{2}-6x+1+p=(ax+b)^{2}=a^{2}x^{2} +2abx+b^{2}$

From comparision, $a^{2}=1; 2ab=-6; b^{2}=1+p\\a=1; b=-3\\(-3)^{2}=p+1\\p=8$

∴ 8 more unit tiles are required to complete the square.

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3 years ago

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