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inn [45]
3 years ago
6

A rectangular floor of area 360 m2 is going to be tiled. Each tile is rectangular, and has an area of 240 cm2. An exact number o

f tiles can be put into the space. How many tiles will be needed?
Mathematics
1 answer:
scoray [572]3 years ago
4 0

Answer:

1500

Step-by-step explanation:

The area of the regtangular floor is 360m². The floor is going to be retired with tiles having area of 240cm² . We need to find the number of times . Therefore ,

\implies 360m^2 = 360 \times 10^4 \ cm^2

And , the number of tiles required will be ,

\implies n =\dfrac{Area \ of \ floor}{Area \ of \ a \ tile }\\\\\implies n =\dfrac{ 360 \times 10^4 \ cm^2}{240 cm^2} \\\\\implies \underline{\underline{ n = 1,500 }}

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>1</u><u>5</u><u>0</u><u>0</u><u> </u><u>.</u>

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HELP PLEASE ASAP
Pie

\bold{\huge{\underline{ Solution }}}

<u>We </u><u>have</u><u>, </u>

  • Line segment AB
  • The coordinates of the midpoint of line segment AB is ( -8 , 8 )
  • Coordinates of one of the end point of the line segment is (-2,20)

Let the coordinates of the end point of the line segment AB be ( x1 , y1 ) and (x2 , y2)

<u>Also</u><u>, </u>

Let the coordinates of midpoint of the line segment AB be ( x, y)

<u>We </u><u>know </u><u>that</u><u>, </u>

For finding the midpoints of line segment we use formula :-

\bold{\purple{ M( x,  y) = }}{\bold{\purple{\dfrac{(x1 +x2)}{2}}}}{\bold{\purple{,}}}{\bold{\purple{\dfrac{(y1 + y2)}{2}}}}

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

  • The coordinates of midpoint and one of the end point of line segment AB are ( -8,8) and (-2,-20) .

<u>For </u><u>x </u><u>coordinates </u><u>:</u><u>-</u>

\sf{  -8  = }{\sf{\dfrac{(- 2 +x2)}{2}}}

\sf{2}{\sf{\times{ -8  = - 2 + x2 }}}

\sf{ - 16 = - 2 + x2 }

\sf{ x2 = -16 + 2 }

\bold{ x2 = -14  }

<h3><u>Now</u><u>, </u></h3>

<u>For </u><u>y </u><u>coordinates </u><u>:</u><u>-</u>

\sf{  8  = }{\sf{\dfrac{(- 20 +x2)}{2}}}

\sf{2}{\sf{\times{ 8   = - 20 + x2 }}}

\sf{ 16 = - 20 + x2 }

\sf{ y2 = 16 + 20 }

\bold{ y2 = 36  }

Thus, The coordinates of another end points of line segment AB is ( -14 , 36)

Hence, Option A is correct answer

7 0
3 years ago
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KATRIN_1 [288]

Answer:

2. b

3. d.

4. c.

Step-by-step explanation:

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Write 11.183 million in scientific notation.
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The answer is 1.1 x10^7
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3 years ago
A football thrown by a quarterback follows a path given by hx=-0.0095x2+x+7, where h is the height of the ball in feet and x is
Wewaii [24]

Answer:

The ball can be knocked down at a horizontal distance of 3.09 feet or 102.17 feet from the marshal.

Step-by-step explanation:

We have the function that represents the height h (x) of the ball h(x) = -0.0095x^2 + x + 7

Where x is the horizontal distance of the ball.

We want to find the horizontal distance the ball is at (horizontal distance between the field marshal and the ball) when it is at a height of 10 feet.

To do this, we must do h (x) = 10

10 = -0.0095x^2 + x + 7\\0 = -0.0095x^2 + x -3

Now we must solve the second degree equation. For this we use the formula of the resolvent:

\frac{-b + \sqrt{b ^ 2 - 4 * a * c}}{2a}

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\frac{-b - \sqrt{b ^ 2 - 4 * a * c}}{2a}


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\frac{-1 - \sqrt{1 ^ 2 - 4 * (- 0.0095)(-3)}} {2 (-0.0095)} = 102.17ft


Then, the ball can be knocked down at a horizontal distance of 3.09 feet or 102.17 feet from the marshal.

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Y= mx+b

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2x-3(-7) = 12
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Insert the values into y = mx + b
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