The length of the line segment AB where

and


We have:

subtitute

Answer: b. 14.1
The answer is B.
This is because A is incorrect, Zach number of minutes didnt increase by an equal factor every month.
C and D are incorrect, Victoria's methods aren't exponential, but Zach's are.
So that leaves the only reasonable answer which is B.
d = 3 , a₁₂ = 40 and S
= 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a

= a₁ + (n-1)d</h3><h3>• S

=

[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =

[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
First term, a
1
=4
Second term, a
2
=8
Common difference, d=a
2
=a
1
d=8−4=4
∴ The common difference is 4
Answer:
b^4 / a
Step-by-step explanation:
I have attached the explanation above. hopefully this will help