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boyakko [2]
3 years ago
7

Which of the following is a solution to the system of equations? y= 3x+24 y=10-0.5x

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

x = -4

y = 12

I hope it helps you

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the coordinates of a line segment are (1,6) and (11, -4). what is the length of the line segment? round your answer to the neare
ddd [48]
The length of the line segment AB where A(x_A;\ y_A) and B(x_B;\ y_B)

|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

We have: A(1;\ 6);\ B(11;-4)

subtitute

|AB|=\sqrt{(1-11)^2+(6-(-4))^2}=\sqrt{(-10)^2+10^2}=\sqrt{100+100}\\\\=\sqrt{100\cdot2}=\sqrt{100}\cdot\sqrt2=10\sqrt2\approx14.1

Answer: b. 14.1
3 0
3 years ago
Zach read a book for 10 minutes every weekend in the first month, 20 minutes in the second month, 40 minutes in the third month,
Lubov Fominskaja [6]
The answer is B.

This is because A is incorrect, Zach number of minutes didnt increase by an equal factor every month.

C and D are incorrect, Victoria's methods aren't exponential, but Zach's are.

So that leaves the only reasonable answer which is B.
5 0
3 years ago
The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(
SVEN [57.7K]

d = 3 , a₁₂ = 40 and Sx_{100} = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• an = a₁ + (n-1)d</h3><h3>• S_n = \frac{n}{2}[2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = \frac{50}{2}[(2×7) +(99×3)</h3><h3>       = 25(14 + 297) = 25(311)= 7775</h3>
7 0
3 years ago
Find the recursive formula.<br> 8, 12, 16, 20, ...
ArbitrLikvidat [17]
First term, a
1
​
=4
Second term, a
2
​
=8
Common difference, d=a
2
​
=a
1
​

d=8−4=4
∴ The common difference is 4
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B3%7Db%5E%7B5%7D%7D%7Ba%5E%7B4%7Db%7D" id="TexFormula1" title="\frac{a^{3}b^{5
aliina [53]

Answer:

b^4 / a

Step-by-step explanation:

I have attached the explanation above. hopefully this will help

3 0
3 years ago
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