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2 years ago

10

How do I solve (2-3*2-3)-4

2 answers:

Anestetic [448]2 years ago

8 0

Do 2-3 times 2-3 then -4

kondor19780726 [428]2 years ago

3 0

According to PEMDAS, parenthesis goes first. Before addition, multiplication is represented in the M of PEMDAS. So you multiply 3 and 2 inside of the parenthesis. That equals to 6. (2-6-3)-4 is what is left. Then, we still have subtraction to be done in the parenthesis. 2 minus 6 is -4, minus 3 is -7. You’re left with -7-4. This equals to -11. Your answer is -11.

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3x-(2x-1)=7x-(3*5x)+(-x+24)

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Answer:

$\boxed{\boxed{\sf x=\frac{23}{10}}\: \sf or \:\boxed{x=2.3}}$

_________________

$\boxed{\sf Step\: By\:Step:- }$

$\sf 3x-\left(2x-1\right)=7x-\left(3\times \:5x\right)+\left(-x+24\right)$

<u>Remove the parentheses:</u>

$\to\sf 3x-\left(2x-1\right)=7x-3\times \:5x-x+24$

<u>Combine like terms:</u>

$\sf ^*7x-x=6x$

$\to\sf 3x-\left(2x-1\right)=6x-3\times \:5x+24$

<u>Multiply 3 and 5x = 15x:-</u>

$\to\sf 3x-\left(2x-1\right)=6x-15x+24$

<u>Combine like terms:</u>

$\sf ^*6x-15x=-9x$

$\to\sf 3x-\left(2x-1\right)=-9x+24$

<u>Expand: 3x-(2x-1)= x+1</u>

$\to\sf x+1=-9x+24$

<u>Subtract 1 from both sides:</u>

$\to\sf x+1-1=-9x+24-1$

$\to\sf x=-9x+23$

<u>Add 9x to both sides:</u>

$\to\sf x+9x=-9x+23+9x$

$\to\sf 10x=23$

<u>Divide both sides by 10:</u>

$\to\sf \cfrac{10x}{10}=\cfrac{23}{10}$

$\to\sf x=\cfrac{23}{10}$

<u>________________________________</u>

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Which four inequalities can be used to find the solution to this absolute value inequality?

natita [175]

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the inequality:

3 ≤ |x + 2| ≤ 6

Hence:

x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)

This gives:

x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

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Find out more on equation at: brainly.com/question/2972832

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