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3 years ago

How do I solve (2-3*2-3)-4

Mathematics

2 answers:

Anestetic [448]3 years ago

8 0

Do 2-3 times 2-3 then -4

kondor19780726 [428]3 years ago

3 0

According to PEMDAS, parenthesis goes first. Before addition, multiplication is represented in the M of PEMDAS. So you multiply 3 and 2 inside of the parenthesis. That equals to 6. (2-6-3)-4 is what is left. Then, we still have subtraction to be done in the parenthesis. 2 minus 6 is -4, minus 3 is -7. You’re left with -7-4. This equals to -11. Your answer is -11.

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The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2

svetlana [45]

Answer:

The equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1$ .

Step-by-step explanation:

Given

The equation of ellipsoid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1$

The equation of tangent plane at the point $\left(x_0,y_0,z_0\right)$

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1$ ( Given)

The equation of hyperboloid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1$

F(x,y,z)= $\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}$

$F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}$

$(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)$

The equation of tangent plane at point $\left(x_0,y_0,z_0\right)$

$\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0$

The equation of tangent plane to the hyperboloid

$\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0$

The equation of tangent plane

$2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2$

Hence, the required equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0$

7 0

3 years ago

I need help with geometry i suck at it very bad

nikdorinn [45]

Answer:

x=20

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

CAN SOMEONE HELP ME WITH THIS I WILL GIVE BRAINLIEST TO THE CORRECT ANSWER

Harlamova29_29 [7]

45. X= 2/3x+11/6
46. X=7
47. X=-28/19
48.X=1/2
59. X=-4/3-2y/3
60.X=-1+y/2 or 1+y/2

6 0

2 years ago

How to find an equation for a line through two given points?

xz_007 [3.2K]

Answer:

The equation of the line is: $y = 0.6x + 0.6$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Two points:

We have these following two points in this exercise:

x = -6, y = -3, so (-6,-3)

x = 4, y = 3, so (4,3)

Finding the slope:

Given two points, the slope is given by the change in y divided by the change in x.

Change in y: 3 - (-3) = 3 + 3 = 6

Change in x: 4 - (-6) = 4 + 6 = 10

$m = \frac{6}{10} = 0.6$

Then

$y = 0.6x + b$

Finding b:

We replace one of the points in the equation to find b. I will use (4,3).

$y = 0.6x + b$

$3 = 0.6*4 + b$

$2.4 + b = 3$

$b = 0.6$

The equation of the line is: $y = 0.6x + 0.6$

4 0

3 years ago

HELP PLEASE THANKS (;

Zielflug [23.3K]

You have 2 equations that are both equal to y. If they are both equal to y, then by the transitive property of equality, they are equal to each other (if a = b, and b = c, then a = c).
5x - 17 = x + 3 and
4x = 20 and x = 5. Now sub in that x value of 5 to solve for y:
y = 5 + 3 and y = 8. So the ordered pair is (5, 8)

5 0

3 years ago